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VikaD [51]
3 years ago
6

I need help real quick please!

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

f(x) - n - move the graph n units down

f(x) + n - move the graph n units up

f(x - n) - move the graph n units right

f(x + n) - move the graph n units left

-------------------------------------------------------------------------

f(x)=x^2\\\\g(x)=f(x)-3=x^2-3

<h3>Answer: g(x) = x² - 3</h3>
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At what rate percent per annum will a sum of money double itself in 5 years​
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Answer:

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Step-by-step explanation:

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-4(j-6(j+k)); use j=-7, and k=-2
VARVARA [1.3K]
f(j,k)=-4(j-6(j+k)\\\\f(-7,-2)=-4(-7-6(-7-2))\\\\f(-7,-2)=-4(-13-9)\\\\f(-7,-2)=-4(-22)\\\\f(-7,-2)=-88
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3 years ago
What are the remaining angle measures if the figure is to be a parallelogram?
goldfiish [28.3K]

The correct answer is  

m∠B ==101°,

m∠C =79°,

m∠D=101°

Step-by-step explanation:

  • As we know that, it is a parallelogram opposite angels are congruent
  • Therefore,  m∠A = m∠C and m∠B =m∠B
  • As we know that, If side a=79 then side c must also be equal to 79
  • When we consider all the angles and add them it must be equal to 360°
  • When we add 79+79 = 158°, which mean a=c= 158°
  • By subtracting all the sides of parallelogram which is 360- 158= 202°
  • If we divide it by 2 then we will get the value of the other side of the angle which is  b and d.
  • Dividing 202 by 2
  • \frac{202}{2} = 101°
  • Therefore, the value of b=d=101°
  • A Parallelogram is a flat shape with an opposite sides parallel and they are equal in length.
  • A parallelogram has four sides, and the opposite sides are parallel and they don't intersect.
3 0
3 years ago
Read 2 more answers
How to determine if a triangle is acute by its sides?
Ann [662]
Use the following ( a,b and c are the lengths of the 3 sides with a the longest side):-

If its acute then a^2 < b^2 + c^2
6 0
4 years ago
2х5y-3z-=14<br> x-2y+=-12<br> -x+ Зу-2z =13
lukranit [14]

Answer:

x = -34/3, y = 1/3, and z = -35/3

Step-by-step explanation:

2х+5y-3z-=14   <u>let's call this </u><u>equation 1.</u>

x-2y=-12   <u>let's call this </u><u>equation 2.</u>

-x+Зу-2z =13  <u>let's call this </u><u>equation 3.</u>

<u>USING </u><u>EQUATION 1</u><u> AND </u><u>EQUATION 3</u><u>.</u>

2х+5y-3z-=14   (EQUATION 1)

-x+Зу-2z =13  (EQUATION 3)

<u>LET'S GET RID OF </u><u>z</u><u>, BY MAKING THE COEFFICIENT OF </u><u>z</u><u> IN THE TWO EQUATION THE SAME. WE WILL MULTIPLY </u><u>EQUATION 1</u><u> BY </u><u>2</u><u> AND </u><u>EQUATION 3</u><u> BY </u><u>3</u><u>.</u>

2х+5y-3z-=14   (EQUATION 1) * 2

-x+Зу-2z =13  (EQUATION 3) * 3

4х+10y-6z-=28   <u>let's call this </u><u>equation 4.</u>

-3x+9у-6z =39  <u>let's call this </u><u>equation 5.</u>

<u>TO GET RID OF </u><u>z</u><u>, WE WILL HAVE TO SUBTRACT </u><u>EQUATION 5</u><u> FROM </u><u>EQUATION 4</u><u> PLEASE TAKE NOTE OF THE SIGNS (-) (+).</u>

4х+10y-6z-=28   (EQUATION 4)

- (-3x+9у-6z =39) (EQUATION 5)

(4x - 3x) + ((+10y) - (+9y)) + ((-6z) - (-6z)) = (28 - 39)

x + y + 0 = -11

x + y = -11  <u>let's call this </u><u>equation 6.</u>

<u>USING </u><u>EQUATION 2</u><u> AND </u><u>EQUATION 6</u><u>, LET'S FIND </u><u>x</u><u> AND </u><u>y</u><u>.</u>

x-2y=-12  (EQUATION 2)

x + y = -11  (EQUATION 6)

<u>x</u><u> has the same coefficient in both equations, which is </u><u>1</u><u>. Let's get rid of </u><u>x</u><u> so we can find the value of </u><u>y</u><u>.</u>

<u>We will subtract </u><u>equation 6</u><u> from </u><u>equation 2</u><u>. Take note of the signs.</u>

x-2y=-12  (EQUATION 2)

- (x + y = -11)  (EQUATION 6)

(x - x) + ((-2y) - (+y)) = ((-12) - (-11))

0 + -3y = -1

-3y = -1

<u>Divide both sides by </u><u>-3</u><u>.</u>

-3y/-3 = -1/-3

y = 1/3

<u>LET'S SUBSTITUTE THE VALUE OF </u><u>y</u><u> INTO</u><u> EQUATION 2</u><u> TO GET THE VALUE OF </u><u>x</u><u>.</u>

x-2y=-12  (EQUATION 2)

x-2(1/3)=-12  

x -2/3 = -12

<u>Add </u><u>2/3</u><u> to both sides.</u>

x -2/3 + (2/3) = -12 + (2/3)

x + 0 = -34/3

x = -34/3

<u>LET'S SUBSTITUTE THE VALUES OF </u><u>x</u><u> and </u><u>y</u><u> INTO</u><u> EQUATION 1</u><u> TO GET THE VALUE OF </u><u>z</u><u>.</u>

2х+5y-3z-=14   (EQUATION 1)

2(-34/3)+5(1/3)-3z-=14  

-68/3 + 5/3 - 3z = 14

-21 - 3z = 14

<u>Add </u><u>21</u><u> to both sides.</u>

-21 + (21) - 3z = 14 + (21)

0 - 3z = 35

-3z = 35

<u>Divide both sides by </u><u>-3</u><u>.</u>

-3z/-3 = 35/-3

z = -35/3 <em>or</em>  

Therefore, x = -34/3, y = 1/3, and z = -35/3

Please thank, rate 5 stars, and give brainliest. Thank you.

6 0
3 years ago
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