Answer:
The value of Mode is 2.43
Step-by-step explanation:
- To find the mode of the given data first we have to arrange it in a increasing order then find out mean and median of the given data
- 0.7,1.7,3,3.2,4.1,5.9,6.6,8.9 is in increasing order
- For finding the median we need to take the average of 4th and 5th terms because we have the no of terms in the sequence is even not odd so we need to take the average the 4th term=3.2 and the 5th term =4.1
- so average =(3.2+4.1)/2=3.65
- so the median is equal to 3.65
- For mean we have to take the average of the data
- so mean= sum of all data /no of data
- mean =(0.7+1.7+3+3.2+4.1+5.9+6.6+8.9)/8=4.26
- so by using the formula we can get mode
- <em>Mode=3×Median-2×Mean</em>
- Mode=3×3.65-2×4.26=2.43
- ∴The value of Mode is given as 2.43
Answer:
7/13
Step-by-step explanation:
You would first have to turn the fraction into an improper fraction to find the reciprocal of the fraction!
1 6/7 = 13/7
Reciprocal means reverse, so reverse the improper fraction of 13/7 to get 7/13!
I hope this helps you!
Answer:
1. they both are the same length and diameter, the difference is thw diameter is a different direction.
2. 4 cm
3. EB and 8 cm
Step-by-step explanation:
Diameter is the length of the circle aross, hope this helps!
Answer:
4*(-10-(-3))=-52
Step-by-step explanation:
just step by step
Answer:
<em>The correct option is C.</em>
Step-by-step explanation:
<u>Root Of Complex Numbers</u>
If a complex number is expressed in polar form as

Then the cubic roots of Z are
![\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Z_1%3D%5Cleft%28%5Csqrt%5B3%5D%7Br%7D%2C%5Cfrac%7B%5Ctheta%7D%7B3%7D%5Cright%29)
![\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Z_2%3D%5Cleft%28%5Csqrt%5B3%5D%7Br%7D%2C%5Cfrac%7B%5Ctheta%7D%7B3%7D%2B120%5Eo%5Cright%29)
![\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Z_3%3D%5Cleft%28%5Csqrt%5B3%5D%7Br%7D%2C%5Cfrac%7B%5Ctheta%7D%7B3%7D%2B240%5Eo%5Cright%29)
We are given the complex number in rectangular components

Converting to polar form


It's located in the second quadrant, so

The number if polar form is

Its cubic roots are
![\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Z_1%3D%5Cleft%28%5Csqrt%5B3%5D%7B2%7D%2C%5Cfrac%7B120%5Eo%7D%7B3%7D%5Cright%29%3D%5Cleft%28%5Csqrt%5B3%5D%7B2%7D%2C40%5Eo%5Cright%29)
![\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Z_2%3D%5Cleft%28%5Csqrt%5B3%5D%7B2%7D%2C40%5Eo%2B120%5Eo%5Cright%29%3D%5Cleft%28%5Csqrt%5B3%5D%7B2%7D%2C160%5Eo%5Cright%29)
![\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Z_3%3D%5Cleft%28%5Csqrt%5B3%5D%7B2%7D%2C40%5Eo%2B240%5Eo%5Cright%29%3D%5Cleft%28%5Csqrt%5B3%5D%7B2%7D%2C280%5Eo%5Cright%29)
Converting the first solution to rectangular coordinates
![z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)](https://tex.z-dn.net/?f=z_1%3D%5Csqrt%5B3%5D%7B2%7D%28%5C%20cos40%5Eo%2Bi%5C%20sin40%5Eo%29)
The correct option is C.