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Natalija [7]
3 years ago
11

Hasksousksvsvwgs PLEASE HELP ​

Mathematics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

1/3 or 0.333333...

Step-by-step explanation:

350% = 3.5

1/3 = 0.3333

9/7 = 12.8571

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Which fraction is close to, but less than 1/2?
qwelly [4]

Answer:

1/9, 2/9, 3/9, 4/9, 1/8, 2/8, 3/8, 1/7, 2/7, 3/7, 1/6, 2/6, 1/5, 2/5, 1/4, 1/3.

Step-by-step explanation:

hope this helps,

8 0
3 years ago
Brittany has 50 beads. 70% of the beads are gold. How many beads does Brittany have?
Ket [755]

Answer: 35 gold beads and 15 non-gold beads

Step-by-step explanation:

70% of 50

.70×50 = 35

50 - 35 = 15

6 0
4 years ago
PLEASE HELP CORRECT ANSWERS ONLY!!
mariarad [96]

Answer:

Associative Property of Reciprocals

5 0
3 years ago
Use the graph of the function to evaluate f(2).
oee [108]
Do you have the picture?
6 0
4 years ago
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
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