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Natalija [7]
3 years ago
11

Hasksousksvsvwgs PLEASE HELP ​

Mathematics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

1/3 or 0.333333...

Step-by-step explanation:

350% = 3.5

1/3 = 0.3333

9/7 = 12.8571

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Geometry. Find the angle
lisabon 2012 [21]

Answer:

x = 10°; Angle A = 84°

Step-by-step explanation:

Angle A + Angle B = 180

5x + 34 + 2x + 76 = 180

7x + 110 = 180

7x = 70

x = 10

Angle A: 5(10) + 34 = 50 + 34 = 84°

7 0
3 years ago
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Given: ​△ACE, BD​∥AE<br><br> Prove: BA/CB=DE/CD<br><br> Drag
gizmo_the_mogwai [7]

Answer:


Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2        Corresponding angles for two        parallel lines BD and AE

Triangle AED ||| BDE                                       Angle angle congruent

...                                                                       By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

6 0
3 years ago
Read 2 more answers
A shirts price was $32, on 6% mark, what is the new price of the shirt
allochka39001 [22]

Answer:

19.20

Step-by-step explanation:

.6 is 6%. X 32

8 0
3 years ago
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3√75<br> simplest rationalizing factor <br> PLEASE DO ANSWER ONLY IF YOU KNOW IT
rjkz [21]

Answer:

the square root of 75 is 8.6

and 8.6 times 3 is

the answer is 25.8

Hope This Helps!!!

4 0
3 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0
3 years ago
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