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damaskus [11]
3 years ago
5

The daily rainfall during a two week period in April was: 1, 0.5, 0.3, 0, 0, 0, 1.1, 0.7, 2, 1.3, 2 inches. What was the median

during the two week period ?
Mathematics
2 answers:
Elanso [62]3 years ago
8 0

The median during the two week period is 1 inch.



posledela3 years ago
3 0

1. Putting the numbers in order:


0, 0, 0, 0.3, 0.5, 0.7, 1, 1.1, 1.3, 2.


2. Find middle number:


Since there is an even number of numbers, there are 2 numbers in the middle. 0.5 and 0.7. This means we add the numbers and divide by 2.


0.7 + 0.5 = 1.2


1.2 ÷ 2 = 0.6


Your answer is 0.6


Hope this helped! Let me knkw if there is anything else l can do!!

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What is the number if 50% of 25% of the number is 96
Nastasia [14]

Answer:

768

Step-by-step explanation:

because 50 percent of the num is 96 you double that and then multiply by four

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2 years ago
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How much did rosemary pay per pound?
velikii [3]

Answer:

0.89

Step-by-step explanation:

2.24/3 = 0.89

She paid 89 cents per pound of tomatoes.

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6 0
2 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
Can someone please help me with this asap ... Please and thank you
OLga [1]

Answer:

Step-by-step explanation:

From the question given in the picture,

a). Since, NR bisects a straight angle ∠MNP,

  ∠MNR ≅ ∠PNR

  m∠MNR + m∠PNR = 180°

  2(m∠MNR) = 180°

  m∠MNR = 90°

  Therefore, ∠MNR and ∠PNR are the right angles.

  Since, QN divides ∠MNR in two parts,

  Therefore, ∠QNR will be an acute angle (less than 90°).

  ∠MNR + ∠SNR = ∠MNS

  90° + ∠SNR = ∠MNS

  Therefore, m∠MNS will be more than 90°.

    ∠MNS will be an obtuse angle (greater than 90°).

(b). Since, NR divides ∠MNP and ∠QNS,

    ∠MNR ≅ ∠PNR

     ∠QNR ≅ ∠SNR

     ∠MNQ ≅ ∠PNS

(c). m∠MNR = 90°

     Since, NR bisects ∠QNS,

     ∠QNR ≅ ∠RNS

     m∠QNR = m∠RNS = 30°

     m∠QNR + m∠RNS = 30° + 30°

     m∠QNR + m∠RNS = 60°

     m∠QNS = 60° [Since, m∠QNS = m∠QNR + m∠RNS]

     m∠QNP = m∠QNS + m∠SNP

     m∠QNP = m∠QNS + (m∠PNR - m∠SNR)

     m∠QNP = 60° + (90° - 30°) = 120°        

4 0
2 years ago
In November, the price of a GizmoPhone was double the price in March. In December, the price was $57, which was $29 less than th
Jet001 [13]
<span>December = $57

</span><span>In December, the price was $57, which was $29 less than the price in November then November price was: $57 + $29 = $86
</span><span>In November, the price of a GizmoPhone was double the price in March. so March: $86 x 2 = $172

answer: the price </span>of a GizmoPhone in March was $172
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