Answer:
y = x^(sin(x))
y = e^(SIN(x)*LN(x))
y' = (COS(x)·LN(x) + SIN(x)/x)*e^(SIN(x)*LN(x))
y' = (COS(x)·LN(x) + SIN(x)/x)*x^(SIN(x))
Answer:
First we will split trapezium on two geometric figure.
One is rectangle and the second is right triangle.
When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.
We will use Pythagorean theorem to find the second cathetus b
b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>
AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm
AC=18.1cm
Good luck!!
Answer:
$0.81
Step-by-step explanation:
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I hope I have helped you
Answer:
0 is the correct answer dude