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Deffense [45]
3 years ago
9

Find the 80th term of the following arithmetic sequence. 16, 23, 30, 37, ......

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

80th term = 569

Sequence = 7n + 9

7(80) + 9 = 569

Step-by-step explanation:

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the school newspaper has a circulation of 500 and sells for $.035 a copy. the students decide to raise the price to increase the
Alik [6]

Let x be the number of times they raise the price on the newspaper. Then the new cost of the newspaper is

.35+.05x

Let y be the newspaper they sell, then the income will be

y(.35+.05x)

Now, we know that the circulation is of 500, assuming that they sold every newspaper at the original price now the number the will sell will be

y=500-20x

Plugging the value of y in the first expression we have that the income will be

\begin{gathered} f(x)=(500-20x)(.35+\text{0}.5x)=175+25x-7x-x^2 \\ =-x^2+18x+175 \end{gathered}

Then the income is given by the function

f(x)=-x^2+18x+175

To find the maximum value of this functions (thus the maximum income) we need to take the derivative of the function,

\begin{gathered} \frac{df}{dx}=\frac{d}{dx}(-x^2+18x+175) \\ =-2x+18 \end{gathered}

no we equate the derivative to zero and solve for x.

\begin{gathered} \frac{df}{dx}=0 \\ -2x+18=0 \\ -2x=-18 \\ x=\frac{-18}{-2} \\ x=9 \end{gathered}

This means that we have an extreme value of the function when x=9. Now we need to find out if this value is a maximum or a minimum. To do this we need to take the second derivative of the function, then

\begin{gathered} \frac{d^2f}{dx^2}=\frac{d}{dx}(\frac{df}{dx}) \\ =\frac{d}{dx}(-2x+18) \\ =-2 \end{gathered}

Since the second derivative is negative in the point x=9, we conclude that this value is a maximum of the function.

With this we conclude that the number of times that they should raise the price to maximize the income is 9. This means that they will raise the price of the newspaper (9)($0.05)=$0.45.

Therefore the price to maximize the income is $0.35+$0.45=$0.80.

4 0
1 year ago
The length of the segment between the points $(2a, a-4)$ and $(4, -1)$ is $2\sqrt{10}$ units. What is the product of all possibl
True [87]

Answer:

-3

Step-by-step explanation:

The length of a segment is

sqrt( ( y2-y1)^2 + (x2-x1) ^2) = 2 sqrt(10)

sqrt( ( a-4 - -1)^2 + (2a -4) ^2) = 2 sqrt(10)

sqrt( ( a-4 +1)^2 + (2a -4) ^2) = 2 sqrt(10)

Combine like terms

sqrt( ( a-3)^2 + (2a -4) ^2) = 2 sqrt(10)

Square each side

( a-3)^2 + (2a -4) ^2) = 4 *(10)

FOIL the left side

a^2 -6a +9   + 4a^2 -16a +16 = 40

Combine like terms

5a^2 -22a +25 = 40

Subtract 40 from each side

5a^2 -22a -15 =0

Factor

(a - 5) (5 a + 3) = 0

Using the zero product property

a-5 =0   5a +3 = 0

a = 5       5a = -3

a=5     a = -3/5

The product of the terms is

5 * -3/5 = -3

5 0
3 years ago
What is the area of this triangle
timama [110]

Answer:

i think its 60

Step-by-step explanation:

base times height then divide by 2

5 0
2 years ago
Read 2 more answers
What is the reason for each step in the solution of the inequality?
Citrus2011 [14]

step 1: Given

step 2: Distributive Property

step 3: Combine Like terms

step 4: Subtraction Property of Order

step 5: Addition property of order

step 6: Division property of order

Step-by-step explanation:

We are given the inequality: -38-3(x+5)>6x-17

We need to match each step with the reasons.

The given steps are:

1.

−38−3(x+5)>6x−17

So, Reason for step 1: Given

2.

−38−3x−15>6x−17

So, Reason for step 2: Distributive Property

3.

−3x−53>6x−17

So, Reason for step 3: Combine Like terms

4.

−9x−53>−17

So, Reason for step 4: Subtraction Property of Order

5.

−9x>36

So, Reason for step 5: Addition property of order

6.

x<−4

So, Reason for step 6: Division property of order

Keywords: Solving inequalities

Learn more about Solving inequalities at:

  • brainly.com/question/1465430
  • brainly.com/question/6703816
  • brainly.com/question/4192226

#learnwithBrainly

7 0
3 years ago
PLEASE HELP!!! (WILL GIVE BRAINLIEST FOR CORRECT ANSWER :)
cestrela7 [59]
-180 is the answer
explanation: order of operations
7 0
2 years ago
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