Given:
3:15 pm - start of first showing.
30 minutes break;
20 minutes late - 2nd showing.
4:50 - start of second showing.
4:50 - 0:20 = 4:30 should be the start of the second showing.
4:00 - 4:30 = 1/2 hour break
3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.
4:50 + 0:45 = 5:35 pm end of the 2nd showing.
Yes, the 2nd showing will be over by 6:30 pm.
Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps
Answer:
4.24
Step-by-step explanation:
Answer:
7 + 6 = 13
13 = 7 + 6
13 – 6 = 7
7 = 13 – 6
Step-by-step explanation:
7 + 13 = 20
13 + 7 = 20
13 – 13 = 0
13 – 0 = 13
7 + 0 = 7
6 + 0 = 6
13 – 0 = 13
13 – 13 = 0
7 + 0 = 7
6 + 0 = 6
13 – 0 = 13
13 – 13 = 0
7 + 6 = 13
13 = 7 + 6
13 – 6 = 7
7 = 13 – 6
Answer:
Average rate of change = 2
Step-by-step explanation:
Find the average rate of change for f(x) = x^2 − 3x − 10 from x = −5 to x = 10.
f(-5) = (-5)^2 − 3(-5) − 10 = 25 + 15 - 10 = 30
f(10) = 10^2 − 3(10) − 10 = 100 - 30 - 10 = 60
Average rate of change:
f(10) - f(-5) 60 - 30 30
-------------------- = ------------------------------- = ----------------------- = 2
10 - (-5) 15 15
