Answer:
A, C
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
the ∠A is adjacent (adj) to AB and opposite (Opp) of BC and AB is the hypotenuse (Hyp) of the triangle
which one of the above trig functions fits that?
sin(Ф) = BC / AC is sin(Ф)= Opp / Hyp , so choice A) works
cos(Ф) = BC / AC is not cos(Ф) = Opp / Hyp so choice B) does not work
cos(Ф) = BA / AC is cos(Ф) = Adj / Hyp so choice C) works
AC / BC is just a ratio it's not the angle , so D) doesn't work
B because it is moved but doesn’t change size
Answer:
A) Gradient = -3
B) 3y - x = 7
Step-by-step explanation:
The curve has the equation;
y = x³ - 6x² + 9x + 1
We are given the pints it passes through as;
A(2,3) and P(3, 1)
A) to find the gradient, we will find the derivative of the given equation.
Thus;
Gradient = y' = 3x² - 12x + 9
At point A, x = 2. Thus;
Gradient = 3(2²) - 12(2) + 9
Gradient = 12 - 24 + 9
Gradient = -3
B) since the gradient of the tangent = -3, it means the gradient of the normal will be; -1/-3 = 1/3
Thus, equation of the normal to the curve at point A will be;
(y - 3) = ⅓(x - 2)
Multiply both sides by 3 to get;
3y - 9 = x - 2
3y - x = 9 - 2
3y - x = 7
Answer is b hope this helps brainleist is appreciated
