Distrivute 0.2 to x and +50 and you get 0.2x+10-6 now for the other side we do the same and we get 1.2x+8 or an easier way... Let's solve your equation step-by-step.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span>Step 1: Simplify both sides of the equation.<span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span>Step 2: Subtract 1.2x from both sides.<span><span><span><span>0.2x</span>+4</span>−<span>1.2x</span></span>=<span><span><span>1.2x</span>+8</span>−<span>1.2x</span></span></span><span><span><span>−x</span>+4</span>=8</span>Step 3: Subtract 4 from both sides.<span><span><span><span>−x</span>+4</span>−4</span>=<span>8−4 </span></span><span><span>−x</span>=<span>4 now you divide by negative x (technically it is -1x=4 so your answer is x=-4</span></span>
Answer:
GJIH - WXYZ I guess I ryt
I’m guessing you subtract 78-52 then divide by original which was 52.. so July is 50% warmer.
Mark owes sally 85.00$ he finds 14 friends to help him pay her back. How much does each friend need to pay? (This includes mark)
The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
![\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20%5Ctext%7BFrom%20the%20graph%2C%20%7D%20%5C%5C%20x1%5Ctext%7B%20%3D%201%2C%20y1%20%3D%201%7D%20%5C%5C%20x2%5Ctext%7B%20%3D%207%2C%20y2%20%3D%209%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%287-1%29%5E2%2B%289-1%29%5E2%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B6%5E2%2B8%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%2010%7D%20%5Cend%7Bgathered%7D)
Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters
