Answer:
3 3/8
Step-by-step explanation:
Correct me if I'm wrong
Answer:
If they are not parallel they will cross.
The angle types that are still congruent are the angles that are the same size.
Step-by-step explanation:
Parallel lines never cross but non parallel lines cross.
<h2><u><em>
Could I please have BRAINLIEST?</em></u></h2>
Answer:
P(A) = 44.44%
P(B) = 50%
P(B|A) = 37.5%
P(B|A) different from P(B).
A and B are independent.
Step-by-step explanation:
If we have a total of 180 students, and 80 of them have a Playstation, we have that P(A) = 80/180 = 0.4444 = 44.44%
If we have 90 students that have a Xbox, we have that P(B) = 90/180 = 0.5 = 50%
If we have 30 students that have both consoles, we have that P(A and B) = 30/180 = 0.1667 = 16.67%
To find P(B|A), we will find for a student that has an Xbox inside the group of students that has a Playstation, that is, we have 30 students in a total of 80 students, so P(B|A) = 30/80 = 0.375 = 37.5%
P(B|A) is different from P(B), the first is 37.5% and the second is 50%, so events A and B are independent events.
Answer:
the answer is B. as you can see from the graph Mitchell spent about 8.00 in an hour so he spent more
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
