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madreJ [45]
3 years ago
15

A football team received 2 penalties for 15 yards each, 7 penalties for 5 yards each and 1 penalty for 19 yards. Write and find

the value of an expression to the change in the field position from those penalties
Mathematics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

-84 yards

Step-by-step explanation:

The football team receiving a penalty will have negative number of yards.

For the first penalty, they received two 15 yard.

Total yards = 2(-15)

= -30 yards

For the second penalty , they received seven five yards

the total yards= 7(-5)

= -35 yards

for the last penalty, they received one 19 yards

Total yards= 1(-19)

= -19 yards

x= -30 + (-35) + (-19)

x = -30-35-19

x = -84 yards

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Svetlanka [38]

Answer:

(See explanation for further details)

Step-by-step explanation:

a) Let consider the polynomial p(x) = 5\cdot x^{3} +2\cdot x^{2} - 6 \cdot x +17. The polynomial is in standards when has the form p(x) = \Sigma \limit_{i=0}^{n} \,a_{i}\cdot x^{i}, where n is the order of the polynomial. The example has the following information:

n = 3, a_{0} = 17, a_{1} = -6, a_{2} = 2, a_{3} = 5.

b) The closure property means that polynomials must be closed with respect to addition and multiplication, which is demonstrated hereafter:

Closure with respect to addition:

Let consider polynomials p_{1} and p_{2} such that:

p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i} and p_{2} = \Sigma \limits_{i=0}^{n}\,b_{i}\cdot x^{i}, where m \geq n

p_{1}+p_{2} = \Sigma \limits_{i=0}^{n}\,(a_{i}+b_{i})\cdot x^{i} + \Sigma_{i=n+1}^{m}\,a_{i} \cdot x^{i}

Hence, polynomials are closed with respect to addition.

Closure with respect to multiplication:

Let be p_{1} a polynomial such that:

p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}

And \alpha an scalar. If the polynomial is multiplied by the scalar number, then:

\alpha \cdot p_{1} = \alpha \cdot \Sigma \limits_{i = 0}^{m}\,a_{i}\cdot x^{i}

Lastly, the following expression is constructed by distributive property:

\alpha \cdot p_{1} = \Sigma \limits_{i=0}^{m}\,(\alpha\cdot a_{i})\cdot x^{i}

Hence, polynomials are closed with respect to multiplication.

4 0
3 years ago
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Ira Lisetskai [31]
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Step-by-step explanation:

Given

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11111nata11111 [884]
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I hope that helps.

6 0
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put everything in the formula
PV=7000/(1+0.035)^9
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7 0
3 years ago
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