-6x²+2x= <br>please with a little explanation

can someone please help me i am failing my math and am very behind my math grade level can someone explain this to me please

xenn [34]

Answer:

The answer to number 7 is -1.25

The answer to number 8 is 1.25

4 0

3 years ago

How many even 5-digit numbers can be formed from the numbers 1, 2, 4, 7, 8 if no digit is repeated in a number? A. 72 B. 120 C.

katovenus [111]

Hello,

Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)

It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24

Thus there are 3*24=72 possibilities.

Answer A

If you do'nt believe run this programm

DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
    FOR i2 = 1 TO 5
        IF i2 <> i1 THEN
            FOR i3 = 1 TO 5
                IF i3 <> i2 AND i3 <> i1 THEN
                    FOR i4 = 1 TO 5
                        IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
                            FOR i5 = 1 TO 5
                                IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
                                    nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
                                    IF nb MOD 2 = 0 THEN
                                        tot = tot + 1
                                    END IF
                                END IF
                            NEXT i5
                        END IF
                    NEXT i4
                END IF
            NEXT i3
        END IF
    NEXT i2
NEXT i1
PRINT "tot="; tot
END

7 0

3 years ago

Prove that the sum of ab and ba is divisible by the sum of a and b

Likurg_2 [28]

Answer:

It is divisible by 11 and (a + b) !

Step-by-step explanation:

Given a two digit number $ab$ , the digits written in reverse order is $ba$ .

Note that a two digit number ab = 10a + b.

For example: 24 = 10(2) + 4

Similarly, ba = 10(b) + a

Now, the sum of the numbers ab and ba = 10a + b + 10b + a

= 11a + 11b

= 11(a + b)

Hence, the sum of any two digit number ab and the reverse of the number ba, is divisible by 11 and (a + b).

Hence, proved.

5 0

3 years ago

Which function has a greater rate of change over the interval [0,2]

Illusion [34]

Answer:

g(x) has a greater average rate of change

Step-by-step explanation:

From the given information, the table is:

-1 7

0 5

1 7

2 13

From this table, we have g(0)=5 and g(2)=13

The average rate of change over [a,b] of g(x) is given by: $\frac{g(b)-g(a)}{b-a}$

This implies that on the [0,2]. the average rate of change is:

$\frac{g(2)-g(0)}{2-0}=\frac{13-5}{2}=\frac{7}{2}=3.5$

Also, we have that: f(0)=-4 and f(2)=-1.

This means that the average rate of change of f(x) on [0,2] is

$\frac{f(2)-f(0)}{2-0}=\frac{-1--4}{2} =\frac{3}{2} =1.5$

Hence g(x) has a greater average rate of change on [0,2]

6 0

3 years ago

Suppose there are two lakes located on a stream. Clean water flows into the first lake, then the water from the first lake flows

never [62]

Answer:

a. For the first lake;

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m·t/200 - m·t²/80000

b. t ≈ 1.00505 hours

c. 200 hours

Step-by-step explanation:

The flow rate of water in and out of the lakes = 500 liters/hour

The volume of water in the first lake = 100 thousand liters

The volume of water in the second lake = 200 thousand liters

The mass of toxic substances that entered into the first lake = 500 kg

The concentration of toxic substance in the first lake = m₁/(100000)

Therefore, we have;

The quantity of fresh water supplied at t hours = 500 × t

The change

The change in the mass of the toxic substance with time is given as follows

dm/dt = (m - m/100000 × 500 × t)/100000

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m/100000 × 500 × t - (m/100000 × 500 × t)/200000 × 500 × t

Using an online tool, we have;

c = m·t/200 - m·t²/80000

b. When c < 0.001 kg per liter, we have m < 0.001 × 100000, which gives m < 100

Substituting gives;

0.001 = (100·t - 0.005·100·t²)/100000, solving with an online tool, gives;

t ≈ 1.00505 hours

c. For maximum concentration, we have;

c = m·t/200 - m·t²/80000

m/200000 = m·t/200 - m·t²/80000

1/200000 = t/200 - t²/80000

dc/dt = d(t/200 - t²/80000)/dt = 0

Solving with an online tool gives t = 200 hours

6 0

2 years ago

-6x²+2x= please with a little explanation​

-6x²+2x= please with a little explanation