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3 years ago

Write the equation of the line in slope-intercept form that passes through the point (-3, 5) and is parallel to y=-2/3x

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

3 0

Answer:

$y = \frac{ - 2}{3} x + 3$

Step-by-step explanation:

since it is parallel to y=-2/3x

therefore its slope is equal to -2/3 as well according to y=mx+b where m is the slope

$\frac{y - 5}{x - ( - 3)} = \frac{ - 2}{3}$

cross multiplication, boom, you got it, y=-2/3x+3

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Answer:

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Step-by-step explanation:

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3 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

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For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

$m_ {1} * m_ {2} = - 1$

The given line is:

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So we have:

$m_ {1} = \frac {5} {2}$

We find $m_ {2}:$ $m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}$

So, a line perpendicular to the one given is of the form:

$y = - \frac {2} {5} x + b$

We substitute the given point to find "b":

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ANswer:

$y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)$

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