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Elanso [62]
3 years ago
15

Write the equation of the line in slope-intercept form that passes through the point (-3, 5) and is parallel to y=-2/3x

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer:

y =  \frac{ - 2}{3} x + 3

Step-by-step explanation:

since it is parallel to y=-2/3x

therefore its slope is equal to -2/3 as well according to y=mx+b where m is the slope

\frac{y - 5}{x - ( - 3)}  =   \frac{ - 2}{3}

cross multiplication, boom, you got it, y=-2/3x+3

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Answer: this is a INVERSE choice C

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2 years ago
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Use the equation to complete an algebraic proof that proves the answer is x = 7/6. Write your proof in your journal and upload y
dimaraw [331]

Answer:

Step-by-step explanation:

Show that if 3x – 7 = 5, then x = 4.

Here, our given statement is 3x – 7 = 5, and we're asked to prove x = 4.

x=4

Statements Reasons

1. 3x – 7 = 5 Given

2. 3x – 7 + 7 = 5 + 7 Addition of 7 to equation (1)

3. 3x + 0 = 5 + 7 Substitution of –7 + 7 = 0 into (2)

4. 3x = 5 + 7 Substitution of 3x + 0 = 3x into (3)

5. 3x = 12 Substitution of 5 + 7 = 12 into (4)

6. 3x⁄3 = 12⁄3 Dividing equation (5) by 3

7. x = 12⁄3 Substitution of 3x⁄3 = x into (6)

8. x = 4 Substitution of 12⁄3 = 4 into (7)

Is there such a thing as being too descriptive? Yep, and that was it, since over half the proof was devoted to telling the reader how to do arithmetic. We'll typically take numerical computation for granted, and write proofs like this:

5 0
3 years ago
I'm stuck, plsss help ASAPP!!! :))
Bogdan [553]

Answer:

15 units

Step-by-step explanation:

d \:  =  \sqrt{(x2 - x1) ^{2}  + (y2 - y1) ^{2} }

d = 14.866

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7 0
3 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

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2 years ago
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liberstina [14]

Answer:

4

Step-by-step explanation:

x= 18÷4.5=4

hope it helps

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2 years ago
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