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Vikki [24]
3 years ago
10

If the sum of five consecutive odd integers is 95, what is the smallest of the five integers?

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

15+ 17+ 19+ 21+23

Step-by-step explanation:

consecutive odd integers, like 1, 3, 5, 7

consecutive even integers, like 2, 4, 6, 8

an integer is a <em><u>whole number</u></em>

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It’s not going to be C because 10 is already in the question
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Jason's mom drove at 100km/hr for a 160km trip.how much longer would the trip have taken if she had driven at 90km/hr
kondor19780726 [428]
We use the formule: t=S/v. So:
+ t1= 160/100 = 8/5 hrs = 5760''
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3 0
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Find the volume of this object
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Answer:

423 cm^{3}

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3 0
3 years ago
I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
Help me pls thanksssss
inessss [21]
×<_ 24 is the answer I believe.
8 0
3 years ago
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