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creativ13 [48]
3 years ago
8

Write an expressiom that is equal to 3 times 2 2/4

Mathematics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

7 1/2

Step-by-step explanation:

2 2/4 can be reduced to 2 1/2

3 times 2 1/2 is 7 1/2

3(2 2/4)= 7 1/2

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y=x+1

Step-by-step explanation:

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1<br> ..S<br> 4 in.<br> Find h.<br> 10 in.<br> h = √[?] in.
blagie [28]

Answer:

√96

Step-by-step explanation:

halve the diameter to set up the pythagorean theorem

2²+b²=10²

4+b²=100

-4 on each side

b²=96

square root each side

b=√96

it could the be further simplified to 4√6

5 0
2 years ago
A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po
Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call h the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is h - 49.

The wire length d is 14 ft longer than height h, hence

d= h+14.

Thus we get a right triangle with hypotenuse d= y+14, perpendicular  h, and base h-49; therefore, the Pythagorean theorem gives

(h-49)^2+h^2 = (h+14)^2

which upon expanding we get:

h^2-98h+2401 = h^2+28h+196

further simplification gives

h^2-126h+2205=0,

which is a quadratic equation with solutions

h =21ft\\h = 105ft.

Since the first solution h =21ft will give the triangle base length of 21ft-49ft = -28ft which is negative; therefore, we disregard it and pick the solution h = 105ft.

Hence, the height of the pole is 105ft.

3 0
3 years ago
A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width is increased by 8, its area is incre
Butoxors [25]

Answer:

Length = 6, Breadth = 2

Step-by-step explanation:

Given:

A rectangle is 3 times as long as it is wide.

If the length is increased by 6 and the width is increased by 8, its area is increased by 108.

Question asked:

Find the original dimensions.

Solution:

Let width of rectangle = x

<u>As given that a rectangle is 3 times as long as it is wide.</u>

Length of rectangle = 3x

Area\ of\ rectangle=length\times breadth

                             =x\times3x=3x^{2}

Now, as given that length is<u> increased by 6</u> and the width is <u>increased by 8,</u>

New length = 3x+6

New breadth = x+8

New area = (3x+6)(x+8)

                =3x(x+8)+6(x+8)\\\\=3x^{2} +24x+6x+48\\=3x^{2} +30x+48

As new area increased  by 108, we can say:-

New area - old area = 108

3x^{2} +30x+48-(3x^{2} )=108\\3x^{2} +30x+48-3x^{2} =108\\\\30x+48=108\\

Subtracting both sides by 48

30x+48-48=108-48\\30x=60

Dividing both sides by 30

x=2

Width of rectangle = x = 2

Length of rectangle = 3x = 3\times2=6

Therefore, original length of rectangle was 6 and original width of rectangle was 2.

3 0
4 years ago
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