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mrs_skeptik [129]
3 years ago
12

Simply the following radical expression

Mathematics
1 answer:
Alja [10]3 years ago
3 0
\sqrt{ \frac{7}{9} }  =   \frac{ \sqrt{7} }{ \sqrt{9} } = \frac{ \sqrt{7} }{3}
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“Express each of the following numbers using scientific notation “
avanturin [10]

11. 1.97 * 10^-6

12. 3.5 * 10^-3

13. 2.28 * 10^13

14. 5.302 * 10^-3

15. 1.64 * 10^1

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Can you see the pattern?

Try the rest yourself

5 0
3 years ago
A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv
mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

p=\frac{1}{6}

Now, probability of failure is given by the formula:

q=1-p=1-\frac{1}{6}=\frac{5}{6}

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

P(x) = ^nC_xp^xq^{n-x}

Plug in all the given values and find the probability of 14 successes. This gives,

P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087

Therefore, the experimental probability of throwing a five is 0.087.

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Step-by-step explanation:

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Step-by-step explanation:

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Find each unknown side length <br> X=<br> Y=
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Answer:

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