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Luden [163]
3 years ago
9

H E L P I M S L O W ! ! !

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

Reflection across the x-axis

Step-by-step explanation:

The points are the same, just opposite of one another. The image looks as if it is a reflection. Think of the x-axis like a puddle and the shape looking into it; try to picture the image seeing its reflection to help.

bulgar [2K]3 years ago
3 0

Answer:

Reflection across the x-axis.

Step-by-step explanation:

The triangles mirror each other with the x-axis acting like said mirror.

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Find the common difference of the arithmetic sequence.<br> -6,-10, -14, -18,
PSYCHO15rus [73]

Answer:

-4

Step-by-step explanation:

Find the common difference of the arithmetic sequence.

-6,-10, -14, -18,

7 0
1 year ago
PLEASE HELP
Ilia_Sergeevich [38]

Answer:

you're correct! the answer is c

Step-by-step explanation:

the factors would be (x+2)(x-3) and when you solve that you get c

5 0
3 years ago
Read 2 more answers
Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
Solve the inequality <br> 21≥t+10
olchik [2.2K]

The answer is t ≤ 11.

  1. Subtract 10 from each side.
  • 21 - 10 ≥ t + 10 - 10
  • t ≤ 11

6 0
2 years ago
What is the domain of y = tan x
levacccp [35]

Answer:

{xIx ≠ π/2 + πn}

Step-by-step explanation:

7 0
4 years ago
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