C. 55
The angle is half of the arc of the circle it cuts in the case 110/2= 55
You can prove this to yourself by knowing that all the circle arcs will always add to the full 360 of a circle, and then that the interior 3 angles of a triangle will always add to 180
So for this case 110+150+100=360
Becomes 55+75+50=180 for the triangle that would be created by the initial angle x
n < 0, is another way to say "n is negative", so let's check
![\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a^n~\hspace{10.5em}\stackrel{n = -n}{a^{-n}}\implies \cfrac{1}{a^n} \\\\\\ a^{-n}~\hspace{10em}\stackrel{n=-n}{a^{-(-n)}}\implies a^{+n}\implies a^n](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bnegative%20exponents%7D%0A%5C%5C%5C%5C%0Aa%5E%7B-n%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5Cqquad%20%5Cqquad%0A%5Ccfrac%7B1%7D%7Ba%5En%7D%5Cimplies%20a%5E%7B-n%7D%0A%5Cqquad%20%5Cqquad%0Aa%5En%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5E%7B-n%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0Aa%5En~%5Chspace%7B10.5em%7D%5Cstackrel%7Bn%20%3D%20-n%7D%7Ba%5E%7B-n%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5C%5C%5C%5C%5C%5C%0Aa%5E%7B-n%7D~%5Chspace%7B10em%7D%5Cstackrel%7Bn%3D-n%7D%7Ba%5E%7B-%28-n%29%7D%7D%5Cimplies%20a%5E%7B%2Bn%7D%5Cimplies%20a%5En%20)
Answer:
I think shape A is just reflected, and make Shape B.
The reflection line is on 2 of the y axis
Step-by-step explanation:
Answer:
x=0,y=-3
Step-by-step explanation:
3x-5y=15 - equation(1)
x-4y=12 => x=12+4y -equation (2)
Replace equation (2) in equation (1)
3(12+4y)-5y=15
36+12y-5y=15
7y=15-36
7y= -21
y = -21/7
y=-3
If y=-3,then replace in equation (1) ; 3x -5(-3)=15
3x+15=15
3x=0
x=0
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