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bazaltina [42]
3 years ago
7

Combine like terms . Please help me I am an vacation and I don't know how to do this

Mathematics
2 answers:
alex41 [277]3 years ago
7 0
I can help with the first problem.

7x to the 4th power is 2401x
5x to the 4th power is 625x

2401x - 625x = 1776x

Hope this helped a bit.
777dan777 [17]3 years ago
4 0
14.2x^4
16.13b-10
18.5y+10
20.5a^3
22.2b^2+8a
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You are parked mile from the football stadium. You walk at a constant rate and it takes you 14 minutes to get to the stadium. Th
eimsori [14]
28 minutes
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find the factors of each number. Write the common factor ( CF ) and then state the greatest common factor ( GCF) .
Reptile [31]

Given:

Two numbers are 12 and 21

To find:

The factors of 12 and 21, then find the common factor and the greatest common factor.

Solution:

Two numbers are 12 and 21. The prime factors of these two numbers are

12=2\times 2\times 3

21=3\times 7

From the above factorization, it is clear that the factor 3 is common in both. So,

Common factor (CF) = 3

Only 3 is common in factorization of both. So,

Greatest common factor (GCF) = 3

Therefore, the common factor is 3 and the greatest common factor is also 3.

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3 years ago
Which expression is equivalent to<br> 3V64k^12
scoundrel [369]

Answer:

I think the answer is C

Step-by-step explanation:

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3 years ago
-x+4y when x=-4/5 and y=1/3
kobusy [5.1K]
The answer is 2.1333 repeating
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3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
mash [69]

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:

y=-16x^2+165x+69

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>

<em />0=-16x^2+165x+69<em />

We can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.

Substitute:

\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}

Evaluate:

\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}

Hence, our solutions are:

\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

7 0
3 years ago
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