Answer:
First option: cos(θ + φ) = -117/125
Step-by-step explanation:
Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.
Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.
Therefore:
cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)
cos(θ + φ) = (-96/125) - (21/125)
cos(θ + φ) = -96/125 - 21/125
cos(θ + φ) = -117/125
Answer:
Step-by-step explanation:
Flip the equation 1) 8a + 2b = 2x
Subtract 2b from both sides 2)8a + 2b(-2b) =<em> 2x + (-2b)</em>
Divide by 8 on both sides 3) 8a/8 =<em> -2b - 2x/8</em>
4) a = 1/-4b + 1/4x
You can arrange them 16 times
1) aabb
2) aabb
3) bbaa
4) bbaa
5) abab
6) abab
7) abab
8) baba
9) baba
10) abba
11) baba
12) baab
13) baab
14) baab
15) baab
16) abba
primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a
![a=\sqrt[]{hipotenusa^2-cateto^2}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7Bhipotenusa%5E2-cateto%5E2%7D)
![a=\sqrt[]{100^2-85^2}=52.68](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7B100%5E2-85%5E2%7D%3D52.68)
a=52.68 m
teniendo el lado faltante podemos calcular las razones trigonometricas
75kg should be the answer
