3 years ago

What is an inequality statement?

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

5 0

An inequality statement is a statement where two values are NOT equal.

You might be interested in

Find the mean of first five natural numbers also find the range of the numbers

ahrayia [7]

Show The pictures please Thank you My friend

4 0

2 years ago

II 3 Find 6 X 915. Show your work.

love history [14]

Answer:

5490

Step-by-step explanation:

you multiply every number by 6 and you will get the answer

4 0

2 years ago

Find the simple interest on a $3,219.00 principal, deposited for six years at a rate of 1.51%.

Karo-lina-s [1.5K]

Answer:

s.i = P. T. R /100

= 3219 . 6 . 1.51 /100

= 29,164.14 / 100

= 291.6414

8 0

3 years ago

Maisha has 3(x+2) hours reading a book 8x-5 hours sleeping and 2x hours playing.How many hours did she spend in all of these act

Mandarinka [93]

Add all the activities together

=3(x+2) + (8x-5) + 2x
multiply 3 by all in parentheses
=(3*x) + (3*2) + (8x-5) + 2x
=3x + 6 + 8x - 5 + 2x
combine like terms
=(3x + 8x + 2x) + (6 - 5)
=13x + 1

ANSWER: 13x + 1

Hope this helps! :)

6 0

3 years ago

What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?

andrew11 [14]

we know that

the standard form of the equation of the circle is

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

$x^{2} +y^{2} +8x-6y+21=0$

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}+8x) +(y^{2}-6y)=-21$

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

$(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9$

$(x^{2}+8x+16) +(y^{2}-6y+9)=4$

Rewrite as perfect squares

$(x+4)^{2} +(y-3)^{2}=4$

$(x+4)^{2} +(y-3)^{2}=2^{2}$

the center of the circle is $(-4,3)$

the radius of the circle is $2\ units$

therefore

the answer is

the radius of the circle is $2\ units$

8 0

3 years ago

Read 2 more answers