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3 years ago

15

A triangle can have at most right angle. 04 01 OO 2

1 answer:

galben [10]3 years ago

6 0

A triangle can only have one right angle. If it had more than one, it would no longer be considered a triangle... It wouldn't have the correct amount of sides and it would be strangely shaped.

The answer would be number 1.

Have a great day/night!

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CAN SOMEONE PLEASE HELP MEEEEE

scoray [572]

Answer:

$22,360

Step-by-step explanation:

Whenever you have a percentage increase, multiply the original value with the percent in decimal form plus one. For example, $21,500 increased by 4% is the equivalent to 21,500 * 1.04. If it decreased by 8%, you would do 21,500 / 1.08.

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3 years ago

As the amount of time on homework increased, their grade in class ____________.

omeli [17]

Answer:

Increases

Step by Step Explanation:

More time on your homework means more time to cheat/figure the answer out.

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3 years ago

Read 2 more answers

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

3 years ago

Use the change of variables s=x+3y, t=y to find the area of the ellipse x2+6xy+10y2≤1.

MArishka [77]

$t=y\implies s=x+3t\implies x=s-3t$

Then

$x^2+6xy+10y^2=(s-3t)^2+6(s-3t)t+10t^2=s^2+t^2\le1$

which is a disk of radius 1, hence with area $\pi$ .

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3 years ago

Solve for x<br>1. 3(x - 3) < 2x – 11

Anni [7]

I’m sure the answer is x=19

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3 years ago