which term describes the point where the perpendicular bisectors of the three sides of a triangle intersect?

GenaCL600 [577]

Answer:

x = 144

Step-by-step explanation:

What you need to remember about this geometry is that all of the triangles are similar. As with any similar triangles, that means ratios of corresponding sides are proportional. Here, we can write the ratios of the long leg to the short leg and set them equal to find x.

x/60 = 60/25

Multiply by 60 to find x:

x = (60·60)/25

x = 144

_____

<em>Comment on this geometry</em>

You may have noticed that the above equation can be written in the form ...

60 = √(25x)

That is, the altitude from the hypotenuse (60) is equal to the geometric mean of the lengths into which it divides the hypotenuse (25 and x).

This same sort of "geometric mean" relation holds for other parts of this geometry, as well. The short leg of the largest triangle (the hypotenuse of the one with legs 25 and 60) is the geometric mean of the short hypotenuse segment (25) and the total hypotenuse (25+x).

And, the long leg of the large triangle (the hypotenuse of the one with legs 60 and x) is the geometric mean of the long hypotenuse segment (x) and the total hypotenuse (25+x).

While it can be a shortcut in some problems to remember these geometric mean relationships, you can always come up with what you need by simply remembering that the triangles are all similar.

3 0

3 years ago

What distribution pattern describes pine trees on a pine tree farm? varied random uniform clumped?

serious [3.7K]

The answer would be uniform

7 0

3 years ago

Read 2 more answers

You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th

Sonja [21]

Answer:

$Quarters = 41$

$Dimes = 18$

Step-by-step explanation:

Given

$Coins = 59$

$Worth = \$12.05$

$d = dimes$

$q = quarters$

Required

The number of each coin

The total coins can be represented as:

$d + q = 59$

$1\ quarter = \$0.25 \\ 1\ dime = \$0.10$

So, the worth of the coin is:

$0.25q + 0.10d = 12.05$

The equations to solve are:

$0.25q + 0.10d = 12.05$

$d + q = 59$

Make d the subject in: $d + q = 59$

$d =59 - q$

Substitute $d =59 - q$ in $0.25q + 0.10d = 12.05$

$0.25q + 0.10(59 - q) = 12.05$

$0.25q + 5.9 - 0.10q = 12.05$

Collect like terms

$0.25q - 0.10q = 12.05 - 5.9$

$0.15q = 6.15$

Solve for q

$q=\frac{6.15}{0.15}$

$q=41$

Substitute $q=41$ in $d =59 - q$

$d = 59 - 41$

$d = 18$

So:

$Quarters = 41$

$Dimes = 18$

5 0

3 years ago

Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√

TiliK225 [7]

Parameterize the part of the sphere by

$\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)$

with $0\le u\le2\pi$ and $0\le v\le\dfrac\pi4$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv$

So the area of $S$ (the part of the sphere above the cone) is given by

$\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi$

4 0

4 years ago

211 times 9=<—round the answer.

Yuki888 [10]

Answer:

211 × 9 is 1899 so rounding to nearest thousands would be 2000

3 0

3 years ago