1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verizon [17]
3 years ago
10

which term describes the point where the perpendicular bisectors of the three sides of a triangle intersect?

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0
Circumcenter for the Apex students :)
You might be interested in
A line passes through the points (-3, -7) and (7, -6). What is its equation in point-slope form?
HACTEHA [7]

Answer:

1/10

Step-by-step explanation:

not sure

3 0
3 years ago
Identify what Number property is shown for each statement
Alecsey [184]

i think answer are big enough

8 0
3 years ago
Find tan A and tan B.
Reika [66]

Answer:

tan A = 2.6         tan B = .38

Step-by-step explanation:

Tangent = side opposite/side adjacent

7 0
3 years ago
Is 12a-a simplified?
7nadin3 [17]
12a−a

=12a−1a

=12a+−1a

=a+a+a+a+a+a+a+a+a+a+a+a+−a

=a+a+a+a+a+a+a+a+a+a+a

=11a

5 0
4 years ago
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
Other questions:
  • Which of the values in the set {2, 3, 4, 5} is a solution to the equation 2x + 4 = 10? (4 points) 2 3 4 5
    13·2 answers
  • Please help me simplify (1/2)^4
    11·2 answers
  • What is (1
    7·1 answer
  • Cuanto es 3 centenas -200
    13·2 answers
  • How many meters are in 6 feet
    10·2 answers
  • Need help again ?!???
    11·2 answers
  • PLEASE HELPPP ASAPPPPP PLEASEEEEEEEEEEEE
    14·1 answer
  • Equation<br><br> Please do it step by step!
    12·2 answers
  • Can you please help and I need help fast ​
    6·2 answers
  • If f(x) = x - 4 and g(x) = 3x + 5, find (f + g)(x).<br><br> A.4x+9<br> B.2x+9<br> C.2x-1<br> D.4x+1
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!