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3 years ago

if the measure of an angle is 30 degrees more than the measure of its supplement, what is the measure of each angle?

Mathematics

1 answer:

Goshia [24]3 years ago

4 0

Supplementary means equal to 180 so the angles would be 75 and 105

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Which number line shows the correct placement of 20%, 1/3, and 2/3?

BigorU [14]

Answer with Step-by-step explanation:

We are given that

20%

When we change percent into fraction we will divide the percent by 100

$\frac{20}{100}=\frac{1}{5}$

$\frac{1}{3}$

$\frac{2}{3}$

We have to find the line which shows the correct placement of given numbers.

Lcm(3,5)=15

$\frac{1\times 3}{5\times 3}=\frac{3}{15}$

$\frac{1\times 5}{3\times 5}=\frac{5}{15}$

$\frac{2\times 5}{3\times 5}=\frac{10}{15}$

7 0

2 years ago

WILL GIVE BRAINLIEST

SVETLANKA909090 [29]

Answer:

The correct option is A.

Step-by-step explanation:

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$ , then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Let y be the profit (in millions) after x years.

From the given graph it is clear that the line passes through the point (1,-100).

The company paid for these costs and made combined profits of $80 million after 4 years. It means the graph passes through the point (4,80).

The line passes through (1,-100) and (4,80). So, the equation of line is

$y-(-100)=\frac{80-(-100)}{4-1}(x-1)$

$y+100=\frac{180}{3}(x-1)$

$y+100=60(x-1)$

$y+100=60x-60$

Subtract 100 from both sides.

$y+100-100=60x-60-100$

$y=60x-160$

The function form is

$f(x)=60x-160$

Therefore, the correct option is A.

6 0

3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago

Evaluate a2 - 6 for a = 4 and b = 17

Natalija [7]

Answer:

The answer is -94 but where is b

Step-by-step explanation:

2(4)-6(17)=-94

7 0

2 years ago

D is the midpoint of line segment GH. GH = 3x - 1 and DH = 16. Find x.

docker41 [41]

Answer:

3x-1=16*2

3x=32+1

3x=33/:3

x=11

Step-by-step explanation:

3 0

3 years ago