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Kay [80]
3 years ago
13

If 8x=4What is 2+12x?

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer:

8

Step-by-step explanation:

If 8x = 4, then you can solve for x by dividing both sides by 8. Therefore, x = 4/8 or 1/2.

Then to solve 2 + 12x you simply plug in 1/2 for x.

2 + 12x

2 + 12(1/2)

2 + 6

8

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16.95x + .05y = 22.95x + .02y
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What are the degree and zeros of the polynomial f(x)=(x-2)^5
kipiarov [429]

Answer: Degree is 5 and zero of polynomial is 2

3 0
3 years ago
What is the solution to the inequality 2n+5| > 1?
hodyreva [135]

Answer:

n < - 3 or n > - 2

Step-by-step explanation:

Inequalities of the type | x | > a , have solutions of the form

x < - a or x > a

Then

2n + 5 < - 1 or 2n + 5 > 1

Solve both inequalities

2n + 5 < - 1 ( subtract 5 from both sides )

2n < - 6 ( divide both sides by 2 )

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OR

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3 0
3 years ago
In a talent show of singing and comedy acts, singing acts are 4.5 minutes long and comedy acts are 3.5 minutes long. The show ha
Alik [6]

Step-by-step explanation:

Let the number of singing act be x

Let the number of comedy act be y

If the total act is 14, then;

x+y = 14..... 1

If singing acts are 4.5 minutes long and comedy acts are 3.5 minutes long and the acts lasts 59 minutes, then:

4.5x + 3.5y = 59 .......... 2

Solve both equation simultaneously for x and y

x+y = 14

45x+35y = 590

.................................

x+y = 14......... *9

9x+7y = 118....... 1

...............................

9x+9y = 126

9x+7y = 118

Subtract both equations

9y-7y = 126-118

2y = 8

y = 8/2

y = 4

Substitute y = 4 into equation 1;

From 1: x+y = 14

x+4 = 14

x = 14-4

x =10

Hence there are 10 singing acts and 4 comedy acts in the show

7 0
3 years ago
True or False? A circle could be circumscribed about the quadrilateral below.
SVEN [57.7K]

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

7 0
3 years ago
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