Just a random guess 22,275 tell me if it right
Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
9514 1404 393
Answer:
$3291.60
Step-by-step explanation:
If the loan is amortized in the usual way, the monthly payment is ...
A = P(r/12)/(1 -(1 +r/12)^(-12t)) . . . . . loan of P at rate r for t years
A = $15,000(0.081/12)/(1 -(1 +0.081/12)^(-12·5)) ≈ $304.86
The total of payments is ...
(60 months) × ($304.86/month) = $18,291.60
Then the profit to the bank is ...
$18,291.60 -15,000 = $3,291.60 . . . bank profit
Answer:
<u>Consider the following identity:</u>
- a³ - b³ = (a + b)(a² - ab + b²)
<u>Let a = 2, b = 1/2</u>
- (2 + 1/2)(2² - 2*1/2 + 1/2²) =
- 2³ - (1/2)³ =
- 8 - 1/8
P(x)=-4(x-15)2+2
P(x)=7
P(7)=-4(7-15)2+2
-4*7-4*-15
P(7)=-28+60+2+2
P(7)=92