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Art [367]
3 years ago
5

Show that sinxtanx=1-cos^2x/cosx

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0
LHS: = \sin x \tan x =  \frac{\sin x \sin x }{\cos x} =  \frac{\sin^2 x}{\cos x} (using \tan x =  \frac{\sin x}{\cos x})

We know \sin^2x + \cos^2x = 1 \Rightarrow \sin^2x=1-\cos^2x so we can replace the sin²x in the LHS expression as follows

\frac{\sin^2x}{\cos x} =  \frac{1-\cos^2x}{\cos x} which is the RHS.
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each morning a gardener uses 24 1/2 gallons of water from a metal reservoir.each afternoon,she adds 15 1/4 gallons of water to t
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Every day, the volume increases by 24 1/2+15 1/4=39 3/4 gallons. So after 5 days, the volume increases by 39 3/4 * 5 = 795/4= 198.75 gallons
3 0
3 years ago
Of the numbers 8, 9, 10, 11, and 12, which are solutions to the inequality 8p<84?
Allushta [10]
<span>8p<84
p<84/8
p<10.5

answer
</span><span>8, 9, 10 are solutions</span>
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3 years ago
Error error error error error
emmainna [20.7K]
Error error error error error error error

8 0
4 years ago
A closet contains n pairs of shoes. If 2r shoes are chosen at random, (where 2r &lt; n), what is the probability that there will
Pie
We are choosing 2
2
r
shoes. How many ways are there to avoid a pair? The pairs represented in our sample can be chosen in (2)
(
n
2
r
)
ways. From each chosen pair, we can choose the left shoe or the right shoe. There are 22
2
2
r
ways to do this. So of the (22)
(
2
n
2
r
)
equally likely ways to choose 2
2
r
shoes, (2)22
(
n
2
r
)
2
2
r
are "favourable."

Another way: A perhaps more natural way to attack the problem is to imagine choosing the shoes one at a time. The probability that the second shoe chosen does not match the first is 2−22−1
2
n
−
2
2
n
−
1
. Given that this has happened, the probability the next shoe does not match either of the first two is 2−42−2
2
n
−
4
2
n
−
2
. Given that there is no match so far, the probability the next shoe does not match any of the first three is 2−62−3
2
n
−
6
2
n
−
3
. Continue. We get a product, which looks a little nicer if we start it with the term 22
2
n
2
n
. So an answer is
22⋅2−22−1⋅2−42−2⋅2−62−3⋯2−4+22−2+1.
2
n
2
n
⋅
2
n
−
2
2
n
−
1
⋅
2
n
−
4
2
n
−
2
⋅
2
n
−
6
2
n
−
3
⋯
2
n
−
4
r
+
2
2
n
−
2
r
+
1
.
This can be expressed more compactly in various ways.
4 0
3 years ago
A dozen plain hats cost $3.60.What is the unit rate of a hat?
antoniya [11.8K]
$0.30

Here's why:
3.60 30
--------- = -----
12 1

3.60 / 12 = .3
12 / 12 = 1
4 0
3 years ago
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