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vlada-n [284]
3 years ago
9

A basketball coach keeps track of the points scored per game for all of her players. She gives a trophy to to the player with th

e highest mean score at the end of the season. Which of the following justifies why she uses the mean instead of the median?
She wants to take unusually of the good and bad games into account
She wants to remove unusually good and unusually bad games from consideration
The mean and median give the same information, so it doesn't matter which one she chooses.
Mathematics
2 answers:
Natasha2012 [34]3 years ago
5 0

Answer:yes

Step-by-step explanation:

Andrei [34K]3 years ago
3 0

Answer:

She wants to take unusually of the good and bad games into account

Step-by-step explanation:

Given that a basketball coach keeps track of the points scored per game for all of her players.  A trophy is given to the player with the highest mean score at the end of the season.

Mean vs median:

Mean is the arithmetic average of all the entries while median is the middle entry after arranging in ascending order.

Median is not affected by extreme items but mean is very much affected by unusually high or low scores.

Here since the trophy is decided to be given to the highest mean score it is obvious that

She wants to take unusually of the good and bad games into account

Because of this only, mean is taken instead of median.

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If y= x+3/6-x, what is the value of y when x =7i?
djverab [1.8K]

Answer:

Option (2)

Step-by-step explanation:

Given :  y = \frac{x+3}{6-x}

If x = 7i

y = \frac{7i+3}{6-7i}

By simplifying denominator of the given rational expression,

y = \frac{7i+3}{6-7i}\times \frac{6+7i}{6+7i}

y = \frac{(7i+3)(6+7i)}{6^2-(7i)^2}

y = \frac{7i(6+7i)+3(6+7i)}{36-49i^2}

y = \frac{42i+49i^2+18+21i}{36+49} [Since, i² = (-1)]

y = \frac{63i-49+18}{85}

y = \frac{63i-31}{85}

y = -\frac{31}{85}+\frac{63}{85}i

Therefore, Option (2) is the correct option.

3 0
3 years ago
Describe how to compare the two decimals 0.6 and 0.8
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Step-by-step explanation:

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3 years ago
If M is the Midpoint of AB, then solve for x find the unknown measures the given segments.
Leto [7]

Answer:

If M is midpoint of AB, then

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4x-5= 2x+11

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AM= 4x-5

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BM=2x+11

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Hope it helps:-)

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3 years ago
NEED HELP ASAP!!!!!!!!!!
Alona [7]

Answer:

i dont know what your asking

Step-by-step explanation:

7 0
3 years ago
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