X²(x - 4) +4 (x - 4)
(x² + 4) (x - 4)
First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)
Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)
Sec∅ = 1/cos∅
= 1/cos(240)
= 1/cos(180 + 60)
= 1/-cos(60)
= 1/(-1/2)
= -2
The negative externalities must be present.
There are 84 possible student body governments
<h3>The number of student body governments</h3>
The given parameters are:
Senior = 7
Junior = 3
Sophomore = 4
The number of student body governments is calculated as:
n = Senior * Junior * Sophomore
This gives
n = 7 * 3 * 4
Evaluate
n = 84
Hence, there are 84 possible student body governments
Read more about combination at:
brainly.com/question/11732255
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