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WITCHER [35]
3 years ago
11

Asset A has an expected return of 15% and a reward-to-variability ratio of .4. Asset B has an expected return of 20% and a rewar

d-to-variability ratio of .3. A risk-averse investor would prefer a portfolio using the risk-free asset and ______.
Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

Asset A

Step-by-step explanation:

Asset A has an expected return of 15% and a reward - to - variability ratio of .4 . Assets B has an expected return of 20% and a reward - to - variability ratio of .3

As reward - to - variability ratio of Asset A is .4 then it will be risk-averse investor.

Asset A is risk- free asset.

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Daniel can by a particular brand of juice in a 6 ounce bottle or a 10 ounce bottle the juice in a 10 ounce bottle contains 150 c
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Answer: There are 90 calories in a 6-ounce bottle.

Step-by-step explanation:

We assume that the quantity of juice in the bottle is directly proportional to the number of calories it contains.

Given: 10 ounces of juice has 150 calories.

i.e. 1 ounce of juice has \dfrac{150}{10} calories.

i.e. 1 ounce of juice has 15 calories.

Now, In 6 ounce of juice, the number if calories = 15 x 6 = 90 calories

Hence, there are 90 calories in a 6-ounce bottle.

7 0
3 years ago
A professor thinks that the students in her statistics class this term are less creative than most students at this university.
choli [55]

Answer:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

Step-by-step explanation:

\mu=35\\n=23\\\=x=33\\s=5\\\alpha=0.1

1. Null and alternative hypothesis

H_{0}:\mu=35\\H_{1}:\mu

2. Significance level

\alpha=0.1\\1-\alpha=0.99

Freedom degrees is given by:

v=n-1\\v=23-1=22

For a sgnificance level of 0,01 and 22 freedom degrees,  t-student distribution value is:

t_{0.01;23}=-2. 5083

3. Test statistic

t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }

t=\frac{33-35}{\frac{5}{\sqrt{23} } }

t=-1,918

In this case, we have an one left tailed analysis, it means that null hypothesis is rejected if t

-1.918>-2.5083

Conclusion:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

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Answer:  the answer is c

Step-by-step explanation:

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