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MA_775_DIABLO [31]
3 years ago
6

HELP PLEASE!

Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0
C or "25 square yards"



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Two groups of tourist fly to Japan. It takes the first group 4 hours less than the second to fly
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Answer:

21

Step-by-step explanation:

think about it this way. if the first group takes 17 hours, and the second group takes 4 hours more than the first group, then how long does the second group take?

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If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x) ?
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Hello,

(t*s)(x)=t(x)*s(x)=(4x²-x+3)*(x-7)

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3b=y+3x 


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Fractions and Mixed numbers:
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28/8 = 3 remainder 4 so 3 4/8(fraction) or 3 1/2
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3 0
3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
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