Its less than bc if you turn them into decimals, 15/53 would be 0.42 and 12/20 would be 0.60
To find the answer I just added all of the dots after the three (amount of books read) and it is equal to 7. :D hope this helped :D
Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Answer:
Solve x2 + 12x = –20 by completing the square.Add to both sides of the equation. The value of in this equation is 36Write the left side of the equation as a binomial squared. The left side of the equation becomes (x+6)2.Use the square root property of equality.Isolate the variable: x = -10 and -2
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
AB = DC Given
AO = BO = OD = DC Def. of radii
ΔOAB ≅ ΔOCD SSS
x = 77° CPCTC