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3 years ago

What is -5 plus -10 minus 41562 times 6

Mathematics

2 answers:

Citrus2011 [14]3 years ago

7 0

Answer:

-249387

Step-by-step explanation:

1) Write out the problem

-5+-10-41562*6

2) Following order of operations, multiply -41562 by 6:

-5+-10-249372

3) Solve -5+-10:

-15-249372

4) Subtract:

-249387

elena55 [62]3 years ago

6 0

Answer:

Your answer is -249387

Step-by-step explanation:

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An aquarium has a base area of 6 square feet and a height of 2 feet. Will the aquarium fit in 15 cubic feet of space? Explain wh

Brums [2.3K]

Answer:

Yes, the aquarium will fit in 15 cubic feet of space.

Step-by-step explanation:

Given:

An aquarium has a base area of 6 square feet and a height of 2 feet.

Now, to find will the aquarium fit in 15 cubic feet of space or not.

So, as given the dimensions:

Base area = 6 square feet.

Height = 2 feet.

Now, to get the volume of aquarium by using formula:

$Volume=base\ area\times height\\\\Volume=6\times 2\\\\Volume=12\ cubic\ feet.$

As, the volume of aquarium is 12 cubic feet.

And, the aquarium to be fit in 15 cubic feet space. So, 15 is more than 12.

Thus, the aquarium will be fit in 15 cubic feet space.

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2 years ago

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

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