All categories

3 years ago

Find the first four iterates of the function f(x) = 7x + 2 if X0= 3.

Mathematics

2 answers:

n200080 [17]3 years ago

6 0

Answer:

The correct answer is B.

Step-by-step explanation:

White raven [17]3 years ago

5 0

It’s b 23,163,1143,8003

You might be interested in

Find the value of m. (-3/4)-⁴×(-3/4)-¹¹ = (-3/4)^m

tatiyna

Answer:

m = - 15

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , then

$(-\frac{3}{4}) ^{-4}$ × $(-\frac{3}{4}) ^{-11}$ = $(-\frac{3}{4}) ^{m}$ , that is

$(-\frac{3}{4}) ^{(-4-11)}$ = $(-\frac{3}{4}) ^{m}$

$(-\frac{3}{4}) ^{-15}$ = $(-\frac{3}{4}) ^{m}$

Equating exponents gives

m = - 15

4 0

2 years ago

Given the function f(x) = –5|x + 1| + 3, for what values of x is f(x) = –12?

Alexus [3.1K]

The answer to your question is negative 52. hope i helped.

7 0

3 years ago

Read 2 more answers

Can you find x I don’t know how.

kodGreya [7K]

Answer:

Step-by-step explanation:

(x+3)/(x+8) = 2/3

3x + 9 = 2x + 16

x = 7

8 0

2 years ago

A bag contains 30 red and blue marbles. If 19 are blue, what fraction of the marbles are blue?

Musya8 [376]

Answer:

19%

Step-by-step explanation:

19/100. i don't think it is that simple, but i did the best i could

5 0

2 years ago

Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

The parameters we have are,

$a=-5,b=-10, c=6$

Plug them in vertex formula,

$x_v=-\dfrac{-10}{2(-5)}=-1$

Plug in the $x_v$ into the equation,

$y_v=-5(-1)^2-10(-1)+6=11$

We now got a point parabola vertex with coordinates,

$(x_v, y_v)\Longrightarrow(-1,11)$

From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

7 0

2 years ago