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sleet_krkn [62]
2 years ago
12

Eduardo bought one dozen bunches of

Mathematics
1 answer:
Serga [27]2 years ago
5 0

30 bunches of seedless grapes can be bought for the rate of 20$

Step-by-step explanation:

<u>Step 1:</u>

one dozen seedless grapes is bought for $8 so that is given by,

one dozen = 12

<u>Step 2 </u><u>:</u>

$8 for one dozen is = 12/8 = 1 and a half dollars or 1.5$ is the cost of a bunch

<u>Step 3:</u>

for 20$, the bunches of seedless grapes that can be bought is given by,

= 20×1.5

= 30

hence with this conclusion we know that 30 bunches of grapes can be bought with $20

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How would I start to solve number 15? Would I use distributive property?
natita [175]
-5-x=2x-(4x+6)

Using the distributive property is the correct first step. (4x+6) is being multiplied by -1, so distributing gives

-5-x=2x+(-4x-6)
-5-x=2x+((-4x)+(-6))

Now, using the associative property of addition, you get

-5-x=(2x+(-4x))+(-6)
-5-x=(2x-4x)-6

Simplify the right hand side:

-5-x=-2x-6

Add 5 and 2x to both sides.

(2x+5)-5-x=(2x+5)-2x-6

On the left side, use the associative property. On the right, commutativity and associativity:

2x+(5-5)-x=5+(2x-2x)-6

Simplify.

2x-x=-1
x=-1
8 0
2 years ago
If a rectangular piece of metal has 27.75 square inches what is the length and width?
svp [43]

We cannot get further information about the dimensions of the piece since the number of variables is greater than the number of equations.

<h3>What are the dimensions of a rectangular piece of metal?</h3>

By geometry we know that the area of the piece of metal is equal to the product of its length and width, then we must find two <em>real</em> numbers such that:

l · w = 27.75, where l, w > 0.

Unfortunately, we cannot get further information about the dimensions of the piece since the number of variables is greater than the number of equations. We need at least one equation to find an <em>unique</em> solution.

To learn more on rectangles: brainly.com/question/15019502

#SPJ1

4 0
2 years ago
5. Leyla will roll a number cube 1-4 and flip a coin. The coin can land on heads or tails. If Leyla rolls the number cube once a
mario62 [17]

Answer:

{4H, 4T}

Step-by-step explanation:

The list that contains only the outcomes where the number cube is more than 3 is given below:

Sample space is

= {1,2,3,4}

The results more than 3 is

S = {3}

After this, the sample space i.e. C when the coin is fippled is

C = {H, T}

Here H denotes the Head

T denotes Tail

So, the outcomes would be

= {4} + {H,T}

= {4H, 4T}

3 0
3 years ago
How do you solve for x? -10 - 2x &gt; 54
expeople1 [14]

Answer:

x< -64

Step-by-step explanation:

hope this helps ;)

4 0
2 years ago
Read 2 more answers
Solve 2x^2+x-4=0<br> X^2+_×+_=0
natima [27]

Answer:

Hopes it helps

Step-by-step explanation:

The Quadratic Polynomial is

2 x² +x -4=0

Using the Determinant method to find the roots of this equation

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0  ∧ x+1=0

x=0     ∧   x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

x=2 ∧ x=-2

As, you will put these values into the equation, you will find that these values does not satisfy both the equations.

So, there is no solution.

You can solve these two equation graphically also.

3 0
2 years ago
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