Answer:184
Step-by-step explanation:
Steps to solve:
4x + 1/3y^2 when x = 2 and y = 3
~Substitute
4(2) + 1/3(3)^2
~Simplify
8 + 1/3(9)
~Simplify
8 + 3
~Add
11
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The half life of the radioactive isotope to the nearest tenth is 0.83 days.
<h3>What is rate of radioactive decay?</h3>
The rate of radioactive decay is the rate at which a radioactive isotope is disintegrated. The half life is the time taken for half of the original amount of radioactive isotope to remain.
Given that;
t/12 = 0.693/k
Where;
t1/2 - half life
k =decay constant
t/12 = 0.693/0.84
t/12 = 0.83 days
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Answer:
a. csc²θ
Step-by-step explanation:
You can use the identities ...
1 +tan² = sec²
cot = cos/sin
sec = 1/cos
csc = 1/sin
___
Then the expression becomes ...

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