5. 12, 6. 14, 7. 36, 8. 17, 9. 8, 10. 24
Answer:
First part representing requirements for the length x>=5 ft
Second part yes
Step-by-step explanation:
Well, the formula for finding the area of a rectangle is l x w. In the question, it states that the pen must be 4 ft wide and to fit his requirements of the pen being at the minimum 20 ft^2 we have this inequality 4x>=20 which we must solve and we get x>=5 which means that this represents all of the possible lengths for the play space. For the second part, we know that to fufill Judah's requirements for square ft., our length must be greater than or equal to 5. Last time I was doing math, I'm pretty sure 5 1/2>5 which thus can be accepted as a length value, still meeting the requirements of at least 20ft^2 space for the play space.
Answer: The answer could be C because is the image of the rotation by 90 degrees clockwise. I hope its right
Answer:
The longest possible values of the other two sides are 7 ft and 14 ft
Step-by-step explanation:
Let one side of the triangle be x and the other, 2x
Perimeter of a triangle = sum of all sides; i.e x+2x+33
Therefore, x+2x+12=33
Solve for x;
3x=33-12
3x=21
Divide both sides by 3; x=21/3
therefore, x=7 and
2x= (2*7) = 14
The longest possible values of the other two sides are 7 ft and 14 ft
