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2 years ago

I’m giving all the points I have, plz help and get it right? Someone please help me

Mathematics

2 answers:

Feliz [49]2 years ago

3 0

Answer:

The area (probability) is: 0.6864.

Step-by-step explanation:

According to the statement, we are in front of a normal distribution with the following parameters:

µ (mean) = 0

σ (Standard deviation) = 1.

Then we need to find the area of the shaded region, which is the area between the points -1.21 < z < 0.84.

And the area (probability) is: 0.6864.

rosijanka [135]2 years ago

3 0

Answer:

A. 0.6864

Step-by-step explanation:

The area of the shaded region between the two z-scores indicated in the diagram is 0.6864.

mean = 0

Standard deviation = 1

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What is the equation of the line that is parallel to the line 5x 2y = 12 and passes through the point (−2, 4)? y = – five-halves

Oduvanchick [21]

Answer:

The answer is

$y = - \frac{5}{2} x - 1$

Step-by-step explanation:

If two equations are parallel it means that both their gradients are equal. We were given the equation:

$5x + 2y = 12$

in order to find the gradient of this equation that we are given we have to ensure that it is in its simplest form:

$5x + 2y = 12 \\ 2y = 12 - 5x \\ \frac{2y}{2} = \frac{12}{2} - \frac{5}{2} x \\ y = 6 - \frac{5}{2} x \: \\ or \: \\ y = - \frac{5}{2} x + 6$

Therefore the gradient of the parallel line with points (-2, 4) is also -5/2

$y = mx + c \\ 4 = - \frac{ 5}{2} ( - 2) + c \\ 4 = \frac{10}{2} + c \\ 4 = 5 + c \\ 4 - 5 = c \\$

$c = - 1 \\ hence \: the \: equation \: for \: the \: \\ parallel \: line \: is \\ \: y = - \frac{5}{2} x - 1$

8 0

2 years ago

What is the following product?

KiRa [710]

ANSWER

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

EXPLANATION

The given product is:

$( \sqrt{14} - \sqrt{3} )( \sqrt{12} + \sqrt{7} )$

We expand using the distributive property to obtain:

$\sqrt{14}( \sqrt{12} + \sqrt{7}) -\sqrt{3}( \sqrt{12} + \sqrt{7} )$

Extract the perfect squares to get:

$\sqrt{14}(2 \sqrt{3} + \sqrt{7}) -\sqrt{3}( 2\sqrt{3} + \sqrt{7} )$

Expand further to get;

$2 \sqrt{42} +7 \sqrt{2}- 2(3) - \sqrt{21}$

This simplifies to,

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

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2 years ago

Find the opposite of 4p3+9p−2 .

stealth61 [152]

-4p^2 - 9p + 2 ezzzzzzz just switch the signs bruhhhh

6 0

3 years ago

Use properties to find the sum or product of 93+(68+7)

zaharov [31]

93 + (68 + 7)
93 + 75
168

7 0

3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$

$P(2>Z)=.97725$

We will use formula $P(a$ to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

$P(-1$

Upon converting 0.81859 to percentage we will get

$0.81859*100=81.859\approx 81.86$

Therefore, 81.86% of final exam score will be between 68 and 86.

3 0

3 years ago