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Alex
2 years ago
11

HELP MEEEEEEEEEEEEEEE

Mathematics
1 answer:
pogonyaev2 years ago
6 0

\dfrac{8^2 \cdot 4^{-3}}{2^4\cdot 8^{-2}}\\\\\\=\dfrac{(2^3)^2\cdot(2^2)^{-3}}{2^4\cdot (2^3)^{-2}}\\\\\\=\dfrac{2^6\cdot2^{-6}}{2^4\cdot 2^{-6}}\\\\\\=\dfrac{2^6}{2^4}\\\\\\=2^{6-4}\\\\\\=2^2\\\\\\=4

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