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4 years ago

How do your write a Noble Gas Configuration for atoms of an element? 40 points!

Chemistry

1 answer:

AlexFokin [52]4 years ago

7 0

Step 1: Find the element on the periodic table.

Step 2: Go back to the last noble gas that was passed (atomic number).

Step 3: Write the symbol of the noble gas in brackets to start your electron configuration. Put the atomic number of the noble gas beneath the symbol to let you know the number of electrons already represented. Take note of the row the noble gas is in on the periodic table.

Step 4: Continue your electron configuration using the row after the noble gas. For example, Krypton ends the 4th row so you would begin with 5. Always begin with the s subshell.

Step 5: Continue writing your electron configuration following the chart until you reach the correct number of electrons.

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Position (m)

Alex777 [14]

Option C. The object is returning to the start at a constant speed.

<h3>Data points of the Position vs Time graph</h3>

The following data points will be used to determine the motion of the object.

<u>Position Time</u>

12 4

10 6

2 8

0 10

From the data above, the position of the object is decreasing towards zero or start point.

Thus, the object is returning to the start at a constant speed.

Learn more about position here: brainly.com/question/2364404

#SPJ1

8 0

2 years ago

Calculate the volume in milliliters of a 0.420mol / L barlum chlorate solution that contains 25.0 g of barium chlorate (Ba(ClO 3

Pachacha [2.7K]

<u>Answer:</u> The volume of barium chlorate is 195.65 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of barium chlorate = 25.0 g

Molar mass of barium chlorate = 304.23 g/mol

Molarity of solution = 0.420 mol/L

Volume of solution = ?

Putting values in above equation, we get:

$0.420mol/L=\frac{25.0\times 1000}{304.23\times V}\\\\V=\frac{25.0\times 1000}{304.23\times 0.420}=195.65mL$

Hence, the volume of barium chlorate is 195.65 mL

6 0

3 years ago

How many joules of heat must be absorbed by 500g h2O @ 50CELCIUS to convert to steam @ 120 celcius?

nadya68 [22]

Answer:

Q = 1267720 J

Explanation:

Qt = QH2O + ΔHv

∴ QH2O = mCpΔT

∴ m H2O = 500 g

∴ Cp H2O = 4.186 J/g°C = 4.183 E-3 KJ/g°C

∴ ΔT = 120 - 50 = 70°C

⇒ QH2O = (500 g)(4.183 E-3 KJ/g°C)(70°C) = 146.51 KJ

∴ ΔHv H2O = 40.7 KJ/mol

moles H2O:

∴ mm H2O = 18.015 g/mol

⇒ moles H2O = (500 g)(mol/18.015 g) = 27.548 mol H2O

⇒ ΔHv H2O = (40.7 KJ/mol)(27.548 mol) = 1121.21 KJ

⇒ Qt = 146.51 KJ + 1121.21 KJ = 1267.72 KJ = 1267720 J

5 0

3 years ago

Question 3

meriva

Answer:

We are dependent on plants and plants need CO2 from enviromen

Explanation:

8 0

3 years ago

Read 2 more answers

In chemical reactions, how does the valence configuration of bromine tend to change?

Strike441 [17]

Answer: Near the Protons. The electron structure of bromine is illustrated above. In chemical reactions, how does the valence configuration of Bromine tend to change? ... It loses one electron.

Explanation:

btw i found that on google lol

3 0

3 years ago