Answer:
Hydrogen, 0,2 mol
Explanation:
= 22, 4 l/mol
V (
) = 6,72
= 6,72 l
V (
) = 6,72
= 6,72 l
The formula is:
n = ![\frac{V}{V_{M} }](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BV_%7BM%7D%20%7D)
n (
) = 6,72l /22,4 l/mol = 0,3 mol
n (
) = 6,72l /22,4 l/mol = 0,3 mol (the same)
But from the equation we get a proportion that 1 mol (
) - 3 mol (
)
(we have more hydrogen than is need for the reaction)
So there is excess of ![H_{2}](https://tex.z-dn.net/?f=H_%7B2%7D)
We only need
= 0,1 mol (
)
0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)
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