Answer:
?
Explanation:
cant help you if there is no question.
The speed of light is 299,792,458 meters per second in vacuum,
somewhat less in any material. How much less depends on the material.
Answer:
Heat transfer in the process is -19.6 kJ
Work done in the process is - 28 kJ
Explanation:
As we know that the process equation is given as
![P_1V_1^{1.1} = P_2V_2^{1.1}](https://tex.z-dn.net/?f=P_1V_1%5E%7B1.1%7D%20%3D%20P_2V_2%5E%7B1.1%7D)
now we know that
![P_1 = 1 bar](https://tex.z-dn.net/?f=P_1%20%3D%201%20bar)
![V_1 = 0.2 m^3](https://tex.z-dn.net/?f=V_1%20%3D%200.2%20m%5E3)
![P_2 = 4 bar](https://tex.z-dn.net/?f=P_2%20%3D%204%20bar)
now from above equation we have
![1(0.2)^{1.1} = 4(V)^{1.1}](https://tex.z-dn.net/?f=1%280.2%29%5E%7B1.1%7D%20%3D%204%28V%29%5E%7B1.1%7D)
![V = 0.057 m^3](https://tex.z-dn.net/?f=V%20%3D%200.057%20m%5E3)
now work done in this process is given as
![W = \frac{P_1V_1 - P_2V_2}{N - 1}](https://tex.z-dn.net/?f=W%20%3D%20%5Cfrac%7BP_1V_1%20-%20P_2V_2%7D%7BN%20-%201%7D)
here we know N = 1.1
so we have
![W = \frac{10^5 (0.2) - 4 \times 10^5(0.057)}{1.1 - 1}](https://tex.z-dn.net/?f=W%20%3D%20%5Cfrac%7B10%5E5%20%280.2%29%20-%204%20%5Ctimes%2010%5E5%280.057%29%7D%7B1.1%20-%201%7D)
![W = -2.8 \times 10^4 J](https://tex.z-dn.net/?f=W%20%3D%20-2.8%20%5Ctimes%2010%5E4%20J)
![W = -28 KJ](https://tex.z-dn.net/?f=W%20%3D%20-28%20KJ)
Now we have
![\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%20%3D%20%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
![T_2 = \frac{P_2V_2 T_1}{P_1V_1}](https://tex.z-dn.net/?f=T_2%20%3D%20%5Cfrac%7BP_2V_2%20T_1%7D%7BP_1V_1%7D)
![T_2 = \frac{4\times 10^5 (0.057) (300)}{10^5 (0.2)}](https://tex.z-dn.net/?f=T_2%20%3D%20%5Cfrac%7B4%5Ctimes%2010%5E5%20%280.057%29%20%28300%29%7D%7B10%5E5%20%280.2%29%7D)
![T_2 = 342 K](https://tex.z-dn.net/?f=T_2%20%3D%20342%20K)
now we have
![\Delta U = \frac{f}{2} n R(\Delta T)](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20%5Cfrac%7Bf%7D%7B2%7D%20n%20R%28%5CDelta%20T%29)
![\Delta U = 3(P_2 V_2 - P_1 V_1)](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%203%28P_2%20V_2%20-%20P_1%20V_1%29)
![\Delta U = 3(4 \times 10^5(0.057) - 10^5(0.2))](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%203%284%20%5Ctimes%2010%5E5%280.057%29%20-%2010%5E5%280.2%29%29)
![\Delta U = 8400](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%208400)
so we have
![Q = \Delta U + W](https://tex.z-dn.net/?f=Q%20%3D%20%5CDelta%20U%20%2B%20W)
![Q = -28 kJ + 8.4 kJ](https://tex.z-dn.net/?f=Q%20%3D%20-28%20kJ%20%2B%208.4%20kJ)
![Q = -19.6 kJ](https://tex.z-dn.net/?f=Q%20%3D%20-19.6%20kJ)
Most of the time heat melts solids. hope that helps :)
Answer:
Explanation:
I dont Understand the question do u have notes or something??