Answer
given,
weight of the oak board = 600 N
Weight of Joe = 844 N
length of board = 4 m
Joe is standing at 1 m from left side
vertical wire is supporting at the end.
Assuming the system is in equilibrium
T₁ and T₂ be the tension at the ends of the wire
equating all the vertical force
T₁ + T₂ = 600 + 844
T₁ + T₂ = 1444...........(1)
taking moment about T₂
T₁ x 4 - 844 x 3 - 600 x 2 = 0
T₁ x 4 = 3732
T₁ = 933 N
from equation (1)
T₂ = 1444 - 933
T₂ = 511 N
Answer:
The total displacement of the car is 250 km.
Explanation:
Given that,
A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of Toronto.
Total displacement = final position - initial position
= 400 km - 150 km
= 250 km
So, the total displacement of the car is 250 km.
Answer:
Magnetic force, F = 0.6 N
Explanation:
It is given that,
Length of the wire, L = 30 cm = 0.3 m
Current carrying in the wire, I = 0.5 A
Uniform magnetic field, B = 4 T
To find,
The magnetic force
Solve,
A force is exerted by the wire in the magnetic field that is given by :
Here,
F = 0.6 N
Therefore, the magnetic force exerted by the wire in the magnetic field is 0.6 N
Answer:
the objects mass is independent of its acceleration in free fall