The digits in the tens place of a two-digit number are 3 more than the digits in the unit place. If the digit at the unit place
be ‘b', then the number is a) 11b + 30 b) 10b + 30 c) 11b + 3 d) 10b + 3
1 answer:
Answer:
A
Step-by-step explanation:
We are told that the number at the unit place is 3 less than the number at the tens place.
So if the number at the units place is b, then the number at the tens place is 10(b+ 3)
So the number is thus;
10(b + 3) + b
= 10b + 30 + b = 11b + 30
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