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wolverine [178]

3 years ago

11

What is the value of x in the equation −x = 4 − 3x + 6? 5 10 −5 −10

1 answer:

Alex3 years ago

5 0

See attached sadfsadf x=5

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Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t

NeTakaya

Answer:

$\mu = 11$

$\sigma = 2.08$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when $Z = -1.44, X = 8$ . So

$Z = \frac{X - \mu}{\sigma}$

$-1.44 = \frac{8 - \mu}{\sigma}$

$8 - \mu = -1.44\sigma$

$\mu = 8 + 1.44\sigma$

Also, when X = 14, Z has a pvalue of 0.925, so when $X = 8, Z = 1.44$

$Z = \frac{X - \mu}{\sigma}$

$1.44 = \frac{14 - \mu}{\sigma}$

$14 - \mu = 1.44\sigma$

$1.44\sigma = 14 - \mu$

Replacing in the first equation

$\mu = 8 + 1.44\sigma$

$\mu = 8 + 14 - \mu$

$2\mu = 22$

$\mu = \frac{22}{2}$

$\mu = 11$

Standard deviation:

$1.44\sigma = 14 - \mu$

$1.44\sigma = 14 - 11$

$\sigma = \frac{3}{1.44}$

$\sigma = 2.08$

7 0

3 years ago

What is the solution to -4(8 - 3x)2 6x - 8?

Fudgin [204]

Answer:

1) -32+12x 2) 2(3x-4)

Step-by-step explanation:

I hope this is right!

7 0

3 years ago

Bryan is buying notebooks and pens at an office supply store. Notebooks cost $3.59 and pens cost $1.49. He can spend up to $13 o

nordsb [41]

3.59x+1.49y=13.00
that should help

4 0

3 years ago

Read 2 more answers

The track-and-field coach wants to know whether the students in the entire school prefer track races or field events. The coach

strojnjashka [21]

All students in each grade

audience: <u>students</u> - counts for both boys and girls.

option (B) for teachers is irrevelant.

option (C) doesn't include girls.

option (D) doesn't include the entire school

Hence, option A is correct.

8 0

2 years ago

Which statement is true about the given function? f(x) < 0 over the intervals (–infinity, –2.7) and (0.8, infinity). f(x) &lt

Lesechka [4]

Answer: f(x) < 0 over the intervals (–infinity, –2.7) and

(–1, 0.8).

Step-by-step explanation:

I got it right

8 0

3 years ago

Read 2 more answers