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castortr0y [4]
3 years ago
13

16. For quadrilateral ABCD, determine the most precise name for it. A(2,3), B (12,3), C(8,6) and D(5,6). Show your work and expl

ain
Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0
Its a quadrilateral if that's what you're asking<span />
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Find the volume of the prism
Kisachek [45]

Answer:

V= l x b x h

= 9cm x 6cm x 12cm

=648

7 0
2 years ago
Need help on this one
Alenkinab [10]
Combine like terms then you have your answers
6 0
3 years ago
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A classic counting problem is to determine the number of different ways that the letters of millennium can be arranged. Find tha
Eddi Din [679]

Answer:

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of letters of the word "millennium" = 10

Letters repeated:

m = 2 times

i = 2 times

l = 2 times

n = 2 times

2. The number of different ways that the letters of millennium can be arranged is:

We will use the n! or factorial formula, this way:

10!/2! * 2! * 2! * 2!

(10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(2 * 1) * (2 * 1) * (2 * 1) * (2 *1)

3'628,800/2*2*2*2 = 3'628,800/16 = 226,800

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

7 0
3 years ago
WRITE Which solid has a greater volume: cone with a base radious of 7 centimeters and a height of 28 centimeters or a pyramid Wi
Mumz [18]
The pyramid has a greater volume.
The volume of the cone is 1436.7 ( to 5 sf )
The volume of the pyramid is 1437.3 ( to 5 sf )
Both of them is 1440 when rounded off to 3 sf. However , the volume of the pyramid is greater.
( so sorry I can’t explain well but I hope it helps )
The solution is in the picture:) hope you understand better!! Sorry if It’s confusing

7 0
3 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
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