Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:

a) P(between 236 and 281 days)

b) a) P(last between 236 and 296)

c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least
data lies within k standard deviation of mean.
For k = 2

Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
Answer:
x=1 y=2
Step-by-step explanation:
Isolate x for 4x -y=2: X=2+y/4
Substitute x= 2+y/4
(2+y/4 )+3y=7
simplify 2+13y/4=7
Isolate y for 2+13y/4=7
y=2
Forx= 2+y/4
Substitute y = 2
x= 2+2/4
Simplify
X=1
A. 1 pound of cherries costs 2.50
B. Yes it is constant
C. I believe that you would put cost on the y and lbs on the x
E. 5 lbs of cherries = 2.50 x 5 = $12.50
2/3 IS GREATER SO THEREFORE YOUR ANSWER WOULD BE '>'
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