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ad-work [718]
3 years ago
3

What is the simplified expression for 3a^2+9ab+5-4a^2-4ab +3?

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
8 0
The answer should be 5ab - a^2 + 8
Verizon [17]3 years ago
7 0

Answer:

-a^2 + 5ab  + 8

Step-by-step explanation:

The given expression is 3a^2 + 9ab + 5 -4a^2 - 4ab + 3

To simplify the expression, we need to identify the like terms and simplify.

<u>Like terms: </u>The like terms are the terms which are having the same variable and the same exponents. The coefficients may be differ.

Examples: i) 3x and -4x are the like terms ii) 3xy^2 and -7xy^2 are the like terms.

Now let's identify the like terms from the given expression.

3a^2, -4a^2 are the like terms

9ab, -4ab are the like terms

5, 3 are the like terms

Now we can combine the like terms and simplify.

3a^2 + 9ab + 5 -4a^2 - 4ab + 3

= (3a^2 - 4a^2) + (9ab - 4ab) + 5+ 3

= -1a^2 + 5ab + 8

= -a^2 + 5ab  + 8

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A pilot is traveling at a height of 30,000 feet above ground she looks down at a angle of depression of 6 and spots runway as me
sukhopar [10]

Distance between runway and pilot position along the ground is 285430.9336 feet that is 53.9464 miles.

<h3><u>Solution:</u></h3>

Given that

Height of position of pilot from the ground = 30000 feet

Angle of depression when he looks down at runway = 6o

Need to measure along the ground, distance between runway and pilot that is horizontal distance between runway and pilot.

Consider the figure attached below

D represents position of runway.  

P represents position of pilot.

PG represents height of position of pilot from the ground that means PG = 30000 feet

PH is virtual horizontal line and HPD is angle of depression means ∠ HPD = 6 degree

AS DG and HP are horizontals, so DG is parallel to HP.

=>  ∠ HPD =∠ PDG =  6 degree  [ Alternate interior angle made by transversal PD of two parallel lines ]

We need to calculate DG

Consider right angles triangle PGD right angles at G

\text {As } \tan x=\frac{\text { Perpendicular }}{\text { Base }}

\tan \angle \mathrm{PDG}=\frac{\mathrm{PG}}{\mathrm{GD}}

\begin{array}{l}{=>\mathrm{GD}=\frac{\mathrm{PG}}{\tan \angle \mathrm{PDG}}} \\\\ {=>\mathrm{GD}=\frac{30000}{\tan 6^{\circ}}=285430.9336}\end{array}

As one foot = 0.000189 miles

=>285430.9336 \text { feet }=285430.9336 \times 0.000189 \text { miles }=53.9464 \text { miles. }

Hence distance between runway and pilot position along the ground is 285430.9336 feet that is 53.9464 miles.

4 0
3 years ago
F(x)=5x-3 find the domain and range
lakkis [162]

Answer:

Let's solve for f.

fx=5x−3

Step 1: Divide both sides by x.

fx

x

=

5x−3

x

f=

5x−3

x

Let's solve for x.

fx=5x−3

Step 1: Add -5x to both sides.

fx+−5x=5x−3+−5x

fx−5x=−3

Step 2: Factor out variable x.

x(f−5)=−3

Step 3: Divide both sides by f-5.

x(f−5)

f−5

=

−3

f−5

x=

−3

f−5

Answer:

x=

−3

f−5

Step-by-step explanation:

Hope I helped

8 0
3 years ago
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The number of tourists visiting a city doubles every month during the two-month period beginning in Jan, 1st and ending
GrogVix [38]

Answer:

2x

Step-by-step explanation:

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2:1

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