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guapka [62]
3 years ago
6

The number of tourists visiting a city doubles every month during the two-month period beginning in Jan, 1st and ending

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

2x

Step-by-step explanation:

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PLS HELP! WILL AWARD BRAINLIEST
NeTakaya

Answer:

5 ft

Step-by-step explanation:

Use Pyth theorem

3^2 + b^2 = 6^2

9 + b^2 = 36

b^2 = 25

b = 5

Plz mark brainliest

5 0
2 years ago
What is the minimum of the sinusoidal function?<br> Enter your answer in the box.
Karolina [17]

•A sinusoidal function is a function in sine or in cosine •The amplitude of a graph is the distance on the y axis between the normal line and the maximum/minimum. It is given by parameter #a# in function #y = asinb(x - c) + d or y = acosb(x - c) + d# •The period of a graph is the distance on the x axis before the function repeats itself. Hope this helps you! :)

4 0
3 years ago
The expression (1/50)(sqrt(1/50)+sqrt(2/50)+sqrt(3/50)+...+sqrt(50/50) is a Riemann Sum approximation for
alexira [117]
\dfrac1{50}\left(\sqrt{\dfrac1{50}}+\sqrt{\dfrac2{50}}+\cdots+\sqrt{\dfrac{50}{50}}\right)=\displaystyle\sum_{n=1}^{50}\sqrt{\dfrac n{50}}\frac1{50}

describes a sum of the areas of 50 rectangles, each of width \dfrac1{50}, and the nth rectangle has height \sqrt{\dfrac n{50}}.

\sqrt{\dfrac n{50}} ranges from a small positive number to 1, which means the integration interval must be [0,1]. The sum is then the right-endpoint Riemann sum of \sqrt x over the interval with 50 equally spaced subintervals, so

\displaystyle\sum_{n=1}^{50}\sqrt{\dfrac n{50}}\frac1{50}\approx\int_0^1\sqrt x\,\mathrm dx

The sum itself evaluates to roughly 0.676, while the exact value of the integral is \dfrac23\approx0.667.
3 0
3 years ago
The equation shown below involves a perfect square trinomial. 4x2 + 20x + 25 = 7 Which of the following is a step in solving thi
fomenos
4 x^2 + 20 x + 25 = 7
Divide both sides by 4:
x^2 + 5 x + 25/4 = 7/4
Write the left-hand side as a square:
(x + 5/2)^2 = 7/4
Take the square root of both sides:
x + 5/2 = sqrt(7)/2 or x + 5/2 = -sqrt(7)/2
Subtract 5/2 from both sides:
x = sqrt(7)/2 - 5/2 or x + 5/2 = -sqrt(7)/2
Subtract 5/2 from both sides:
Answer:  x = sqrt(7)/2 - 5/2 or x = -5/2 - sqrt(7)/2
3 0
4 years ago
What is the input value of f(x)=−2
Korolek [52]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
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