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3 years ago

What is the greatest common factor of 2 16 and 12

Mathematics

1 answer:

Margaret [11]3 years ago

8 0

Step-by-step explanation:

The factors for 16 are 1, 2, 4, 8, 16. The two numbers (12and 16) share common factors (1, 2, 4). The greatest of these is 4 and that is the greatest common factor.

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How do you know what angle degree goes on each corner?

Dahasolnce [82]

Let'sSo, we gave 2 parallel lines and 2 transversals, we have to match the angles.

Let's start with angle b,

$\begin{gathered} b+65=180\text{ (angles in a straight line)} \\ b=180-65 \\ b=115^o \end{gathered}$

Let's move on to angle e,

$\begin{gathered} e=b\text{ (Vertically opposite angles)} \\ \text{but b = 115}^o \\ e=115^o^{} \end{gathered}$

Let's move on to angle d,

$d=110^o\text{ (V}ertically\text{ opposite angles)}$

Moving to angle c, we have;

$c=45^o\text{ (Vertically opposite angles)}$

And, angle a;

$\begin{gathered} a=b\text{ (Alternate angles)} \\ a=115^o \end{gathered}$

8 0

1 year ago

When Ranim started karate, her highest kick went 110^\circ110 ∘ 110, degrees from the ground. Her instructor asked her to practi

gayaneshka [121]

Answer:

Step-by-step explanation:

155° - 110° = 45°

7 0

2 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago

Find the quadratic equation whose roots are -3 and 1

Dmitrij [34]

Answer:

x²+2x-3=0

According to Vieta's formula:

x²-(Sum of roots)x+(product of roots)=0

Sum of roots=-3+1=-2

Product of roots=-3×1=-3

The equation is x²-(-2)x+(-3)=0

x²+2x-3=0

8 0

2 years ago

Write in slope-intercept form an equation of the line that passes through

leva [86]

Step-by-step explanation:

m= (4-0)/(2-1)

y-int=1

y=mx+c

y=4x+1

3 0

2 years ago