Q is negative two thirds which is written as -2/3
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
4x+1/5
I hope this helps! I'm hoping google translated your question properly, I'm native english speaking
¡Espero que esto ayude! Espero que google tradujera tu pregunta correctamente, soy nativo de habla inglesa
Answer:
TU ≈ 12.96
Step-by-step explanation:
Using the Altitude on Hypotenuse theorem
(leg of outer triangle)² = (part of hypotenuse below it) × (whole hypotenuse)
TU² = UV × SU = 6 × 28 = 168 ( take square root of both sides )
TU = 
≈ 12.96 ( to the nearest hundredth )
