Simplify 1/2x - 2/3 + 7/8x + 5/6
2 answers:
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Answer:
The maximum safe rescue height is 104.6 feet above the height of the ground.
Step-by-step explanation:
Consider a triangle ABC where C is the point where the rescue ladder is standing and AB be the building and Ladder making an angle of 72° as shown.
We have to find the height of the building.
Let x be the height of building
Using Trigonometric ratio,
So, the maximum safe rescue height is 104.6 feet above the height of
the ground.
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,
and
Angle θ is given by
Given that a = 4 units, b = 5 units, and c = 9 units, thus
To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus
Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
Using pythagoras theorem,
and
Angle θ is given by
Given that a = 4 units, b = 5 units, and c = 9 units, thus
To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus
Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.