The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²
Answer:
3/4,3/4,3/4,3/4,1,1,2,11/2,11/2,11/4,11/4
Step-by-step explanation:
we just arrange the number from the smallest to bigger
833
Seravalle____________Chiesanuova______________San Marino
|---------------------------------------------------------------------|
982
so the distance from Chiesanuova to Serravalle is :
982 - 833 = 149 miles <==
Answer:
-0.8x + 4.8y + 16
Step-by-step explanation:
4(0.5x+2.5y-0.7x-1.3y+4) = 4( 0.5x - 0.7x + 2.5y - 1.3y + 4)
= 4( -0.2x + 1.2y + 4)
= 4*(-0.2x) + 4 *1.2y + 4*4
= -0.8x + 4.8y + 16
Answer:
Step-by-step explanation:
Area of the trapezoid = area of rectangle + 2 * area of triangle
Area of a triangle = 1/2 bh
= 1/2 * 13 * 7
= 45.5 units²
Area of a rectangle = L × B
= 15 × 13
= 195 units²
Area of the trapezoid = [195 + 2 * (45.5)]
= 195 + 91
= 286 units²